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3 years ago

0.8 as a fraction in simplest form

Mathematics

2 answers:

leonid [27]3 years ago

8 0

^ I agree with that it’s 4 over 5

Tju [1.3M]3 years ago

7 0

The answer would be 4 over 5 or 4/5

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Can someone help me please??

Mariulka [41]

The determinant is 45

5 0

3 years ago

A sales team estimates that the number of new phones they will sell is a function of the price that they set. They estimate that

USPshnik [31]

Answer:

$204

Step-by-step explanation:

The question is at what price x will the company maximize revenue.

The revenue function is:

$R(x) = 4,080x-10x^2$

The price for which the derivate of the revenue function is zero is the price the maximizes revenue:

$R(x) = 4,080x-10x^2\\\frac{dR(x)}{dx}=0=4,080-20x\\x=\frac{4,080}{20}\\ x=\$204$

The company will maximize its revenue when the price is $204.

7 0

4 years ago

Amy had homework for math,science,and history.she spent 1/3 of her time working on math and 1/4 of her time working on science.

Alja [10]

First we need to multiply to make the fractions have equal denominators so we can add/subtract.

math: 1/3 x 4/4=4/12
science: 1/4 x 3/3=3/12

Now we can find the time she spent on history (I assume this is what you are looking for)

Total time-math time<span>-science time=history time</span>
12/12-4/12-3/12
=5/12

Amy spent 5/12 of her time working on history.

8 0

3 years ago

Read 2 more answers

In Applied Life Data Analysis (Wiley, 1982), Wayne Nelson presents the breakdown time of an insulating fluid between electrodes

ale4655 [162]

Answer:

The sample mean is $\bar{x}=14.371$ min.

The sample standard deviation is $\sigma = 18.889$ min.

Step-by-step explanation:

We have the following data set:

$\begin{array}{cccccccc}0.15&0.82&0.81&1.44&2.70&3.28&4.00&4.70\\4.96&6.49&7.25&8.03&8.40&12.15&31.89&32.47\\33.79&36.80&72.92&&&&&\end{array}$

The mean of a data set is commonly known as the average. You find the mean by taking the sum of all the data values and dividing that sum by the total number of data values.

The formula for the mean of a sample is

$\bar{x} = \frac{{\sum}x}{n}$

where, $n$ is the number of values in the data set.

$\bar{x}=\frac{0.15+0.82+0.81+1.44+2.7+3.28+4+4.7+4.96+6.49+7.25+8.03+8.4+12.15+31.89+32.47+33.79+36.80+72.92}{19}\\\\\bar{x}=14.371$

The standard deviation measures how close the set of data is to the mean value of the data set. If data set have high standard deviation than the values are spread out very much. If data set have small standard deviation the data points are very close to the mean.

To find standard deviation we use the following formula

$\sigma = \sqrt{ \frac{ \sum{\left(x_i - \overline{x}\right)^2 }}{n-1} }$