I will be using the language C++. Given the problem specification, there are an large variety of solving the problem, ranging from simple addition, to more complicated bit testing and selection. But since the problem isn't exactly high performance or practical, I'll use simple addition. For a recursive function, you need to create a condition that will prevent further recursion, I'll use the condition of multiplying by 0. Also, you need to define what your recursion is.
To wit, consider the following math expression
f(m,k) = 0 if m = 0, otherwise f(m-1,k) + k
If you calculate f(0,k), you'll get 0 which is exactly what 0 * k is.
If you calculate f(1,k), you'll get 0 + k, which is exactly what 1 * k is.
So here's the function
int product(int m, int k)
{
if (m == 0) return 0;
return product(m-1,k) + k;
}
N+9
The other factor is n-6
Once multiple together, you will get the same equation again
Answer: actually its 4
Step-by-step explanation:
Answer:
t=20
Step-by-step explanation:
delta math blessed.
The hypotenuse length is √(4*4 + 3*3) = 5 (not √7 I suppose)
The area is base*half height = 4*3/2 = 6.
In short, I don't think complex numbers really interfere here.
