Answer:
1764 ways
Step-by-step explanation:
Number of ways of selecting 6 cows from 9 cows and 5 buffaloes from 7
Using the combination formula:
nCr = n! ÷ (n - r)! r!
Ciw selection:
9C6 = 9! ÷ (9-6)! 6!
9C6 = 84
Buffalo Selection:
7C5 = 7! ÷ (7-5)! 5!
7C5 = 21
9C6 * 7C5
84 * 21
= 1764 ways
Let's consider each of the options;
A) The range is the values that y can be of the function f(x). We can see that no matter what x values you put in, f(x)>0. It will never be negative. Although, if you put (1/2)^2, you can get a y value of (1/4) so this statement is incorrect.
B) It would have to put in the x or y value into the function and check. f(0)=(1/2)^0
You know that anything to the zero-th power gives 1, therefore, this statement is correct.
C) Again, if you put in a value such as (1/2)^2, you would be getting a number that is smaller than 1/2, so it isn't always increasing.
D) Again, it is possible to input any value in x and you would still be getting a positive y-value, therefore, this statement is incorrect.
Hope I helped :)
Answer:
x=y-44 and x+y=410
Step-by-step explanation:
So, you want to use the equations x=y-44 and x+y=410 when x is Ann's score and y is Ruth's score. This is because x (Ann's score) is Ruth's score (y) but 44 less, so you subtract y-44 to get x. Then x+y would also have to equal 410 so that's the other equation. Graphing the 2 equations gets you to the point (183,227) in which Ann's score is 183 points and Ruth's score is 227 points.
Where is it the circle ????