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3 years ago

Marty buys 12 ounces of granola. What fraction of a pound of granola did Marty buy

Mathematics

2 answers:

pashok25 [27]3 years ago

5 0

The fraction would be 12/16 because there is 16 ounces in 1 pound.

Mamont248 [21]3 years ago

5 0

The answer would be 12/16 because there is 16 ounces in a pound

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Complete rate table for spaghetti ingredients 12 ounces of spaghetti sauce need 16 ounces of tomato’s what does 1 oz sauce equal

Svetllana [295]

Answer:

I think its 1 1/3 or 1.333

Step-by-step explanation:

divided 16 by 12 bc 12 divided by 12 makes the 1

4 0

4 years ago

Round 363 to the nearest ten and hundred

IRISSAK [1]

Its 400 because 363 is closer to 400 than 300

3 0

4 years ago

Read 2 more answers

21.) A rectangle has an area of 36 square units. As the length and width change, what do you know about their

natima [27]

Answer:

the length and the width are inversely proportional to each other ( $l=\frac{36}{w}$ or $w=\frac{36}{l}$ )

Step-by-step explanation:

Let

l units = length of the rectangle,

w units = width of the rectangle.

The area of the rectangle is

$\text{Area}=\text{Length}\cdot \text{Width}$

A rectangle has an area of 36 square units, so

$l\cdot w=36$

Complete the table with some values of l and w that fit the previous formula:

$\begin{array}{ccc}\text{Length}&\text{Width}&\text{Area}\\ \\36&1&36\cdot 1=36\ un^2.\\18&2&18\cdot 2=36 \ un^2.\\12&3&12\cdot 3=36\ un^2.\\ 9&4&9\cdot 4=36\ un^2.\\l&w&l\cdot w=36 \ un^2.\end{array}$

As you can see, the length and the width are inversely proportional to each other ( $l=\frac{36}{w}$ or $w=\frac{36}{l}$ )

4 0

4 years ago

What is the volume, in cubic inches, of a basketball with a diameter of 9 inches?

nlexa [21]

Answer:

381.70350741116 inches^3

Step-by-step explanation:

4/3 πr^3 = 4/3 x π x 4.5^3 = 381.70 inches ^3

5 0

4 years ago

In 2002, the mean age of an inmate on death row was 40.7 years with a standard deviation of 9.6 years according to the U.S. Depa

marissa [1.9K]

Answer:

The 95% confidence interval for the current mean age of death-row inmates is between 42.23 years and 35.57 years.

Step-by-step explanation:

The confidence interval of the mean is given by the next formula:

$\\ \overline{x} \pm z_{1-\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$ [1]

We already know (according to the U.S. Department of Justice):

The (population) standard deviation for this case (mean age of an inmate on death row) has a standard deviation of 9.6 years ( $\\ \sigma = 9.6$ years).
The number of observations for the sample taken is $\\ n = 32$ .
The sample mean, $\\ \overline{x} = 38.9$ years.

For $\\ z_{1-\frac{\alpha}{2}}$ , we have that $\\ \alpha = 0.05$ . That is, the level of significance $\\ \alpha$ is 1 - 0.95 = 0.05. In this case, then, we have that the z-score corresponding to this case is:

$\\ z_{1-\frac{\alpha}{2}} = z_{1-\frac{0.05}{2}} = z_{1-0.025} = z_{0.975}$

Consulting a cumulative standard normal table, available on the Internet or in Statistics books, to find the z-score associated to the probability of, $\\ P(z$ , we have that $\\ z = 1.96$ .

Notice that we supposed that the sample is from a population that follows a normal distribution. However, we also have a value for n > 30, and we already know that for this result the sampling distribution for the sample means follows, approximately, a normal distribution with mean, $\\ \mu$ , and standard deviation, $\\ \sigma_{\overline{x}} = \frac{\sigma}{\sqrt{n}}$ .

Having all this information, we can proceed to answer the question.

Constructing the 95% confidence interval for the current mean age of death-row inmates

To construct the 95% confidence interval, we already know that this interval is given by [1]:

$\\ \overline{x} \pm z_{1-\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$

That is, we have:

$\\ \overline{x} = 38.9$ years.

$\\ z_{1-\frac{\alpha}{2}} = 1.96$

$\\ \sigma = 9.6$ years.

$\\ n = 32$

Then

$\\ 38.9 \pm 1.96*\frac{9.6}{\sqrt{32}}$

$\\ 38.9 \pm 1.96*\frac{9.6}{5.656854}$

$\\ 38.9 \pm 1.96*1.697056$

$\\ 38.9 \pm 3.326229$

Therefore, the Upper and Lower limits of the interval are:

Upper limit:

$\\ 38.9 + 3.326229$

$\\ 42.226229 \approx 42.23$ years.

Lower limit:

$\\ 38.9 - 3.326229$

$\\ 35.573771 \approx 35.57$ years.

In sum, the 95% confidence interval for the current mean age of death-row inmates is between 42.23 years and 35.57 years.

Notice that the "mean age of an inmate on death row was 40.7 years in 2002", and this value is between the limits of the 95% confidence interval obtained. So, according to the random sample under study, it seems that this mean age has not changed.

7 0

4 years ago