Write the equation of the line that passes through (0, 3) and is parallel to the line 3x + 5y = 6.
1 answer:
Please, see the offered decision:
1) common equation for lines is y=kx+b. If k₁=k₂ (for line 1 and line 2) ⇒ 'line 1' || 'line 2'.
2) for line 3x+5y=6 k= -3/5. It means (according to item 1) for unknown line k is the same (-3/5).
3) using points (0;3) it is easy to find parameter b (x=0, y=3) via y=kx+b:
3=0*(-3/5)+b ⇔ b=3.
4) finaly (k=-3/5; b=3):
1) common equation for lines is y=kx+b. If k₁=k₂ (for line 1 and line 2) ⇒ 'line 1' || 'line 2'.
2) for line 3x+5y=6 k= -3/5. It means (according to item 1) for unknown line k is the same (-3/5).
3) using points (0;3) it is easy to find parameter b (x=0, y=3) via y=kx+b:
3=0*(-3/5)+b ⇔ b=3.
4) finaly (k=-3/5; b=3):
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See attachment for the drawing of the perpendicular at a point c on line ab such the ac = 3.5 cm
<h3>How to draw the perpendicular at a point c on line ab such the ac = 3.5 cm?</h3>The given parameters are:
Length of segment AB = 7 cm
Also, we have:
Point C is located on line segment AB
This means that:
Length of segment AC = Length of segment BC = 3.5 cm
When represented on a line segment, we have:
A C B
See attachment for the drawing of the perpendicular at a point c on line ab such the ac = 3.5 cm
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