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erma4kov [3.2K]
3 years ago
6

Based on the equation 3x + 8y = 48, what is the missing value in the table?

Mathematics
2 answers:
defon3 years ago
6 0

Answer:6

Step-by-step explanation:

shtirl [24]3 years ago
3 0

Answer: 6

Step-by-step explanation: On Edgenuity!!!!!!!!!!!!!!!!!!!!!!!!!!

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What is the nearest integer of cube root -12
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Step-by-step explanation:

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2 years ago
Find the area of the shaded region. Round your answer to the nearest tenth.
Alex
Check the picture below on the left-side.

we know the central angle of the "empty" area is 120°, however the legs coming from the center of the circle, namely the radius, are always 6, therefore the legs stemming from the 120° angle, are both 6, making that triangle an isosceles.

now, using the "inscribed angle" theorem, check the picture on the right-side, we know that the inscribed angle there, in red, is 30°, that means the intercepted arc is twice as much, thus 60°, and since arcs get their angle measurement from the central angle they're in, the central angle making up that arc is also 60°, as in the picture.

so, the shaded area is really just the area of that circle's "sector" with 60°, PLUS the area of the circle's "segment" with 120°.

\bf \textit{area of a sector of a circle}\\\\&#10;A_x=\cfrac{\theta \pi r^2}{360}\quad &#10;\begin{cases}&#10;r=radius\\&#10;\theta =angle~in\\&#10;\qquad degrees\\&#10;------\\&#10;r=6\\&#10;\theta =60&#10;\end{cases}\implies A_x=\cfrac{60\cdot \pi \cdot 6^2}{360}\implies \boxed{A_x=6\pi} \\\\&#10;-------------------------------\\\\

\bf \textit{area of a segment of a circle}\\\\&#10;A_y=\cfrac{r^2}{2}\left[\cfrac{\pi \theta }{180}~-~sin(\theta )  \right]&#10;\begin{cases}&#10;r=radius\\&#10;\theta =angle~in\\&#10;\qquad degrees\\&#10;------\\&#10;r=6\\&#10;\theta =120&#10;\end{cases}

\bf A_y=\cfrac{6^2}{2}\left[\cfrac{\pi\cdot 120 }{180}~-~sin(120^o )  \right]&#10;\\\\\\&#10;A_y=18\left[\cfrac{2\pi }{3}~-~\cfrac{\sqrt{3}}{2} \right]\implies \boxed{A_y=12\pi -9\sqrt{3}}\\\\&#10;-------------------------------\\\\&#10;\textit{shaded area}\qquad \stackrel{A_x}{6\pi }~~+~~\stackrel{A_y}{12\pi -9\sqrt{3}}\implies 18\pi -9\sqrt{3}

7 0
3 years ago
X = (y + 3) / 12 solve for y
slega [8]

Answer:

y = 12x-3

Step-by-step explanation:

X = (y + 3) / 12

Multiply each side by 12 to clear the fraction

12 x = (y+3)/12 *12

12x = y+3

Subtract 3 from each side

12x -3 = y+3-3

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3 years ago
Find the slope of the line passing through the points (-8,-8) and (2,-8)
san4es73 [151]

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The slope is -8 :)

Step-by-step explanation:

trust me

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