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3 years ago

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Please please answer! Thank you in advance. Your help is appreciated very much. Also, if you don’t mind may you give me an expla

nation. You don’t have to, but I’d greatly appreciate it.

1 answer:

serious [3.7K]3 years ago

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Each peach weighs 25 ounces

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Write the equation of this line in Point-Slope Form.

Leona [35]

Answer:

y -3 = (-1/2)(x - 5)

Step-by-step explanation:

Slope of line: Notice that if we go from 7 to 5, the 'run' is -2 and the corresponding 'rise' from 2 to 3 is 1. Thus, the slope is m = -1/2.

Using m = -1/2 and the point (5, 3), we write the equation of this line in point-slope form as:

y -3 = (-1/2)(x - 5)

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3 years ago

Gertie ran 3/4 mile during physical education class. Sarah ran 2/4 mile during the same class. How much farther did Gertie run t

Marizza181 [45]

Gertie 3/4 mile.

Sarah 2/4 mile.

Gertie ran farther by: 3/4 - 2/4 = (3 -2)/4 = 1/4

Gertie ran farther by 1/4 mile.

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3 years ago

Read 2 more answers

Exercise 1.2 1 Round each of these numbers to the degree of accuracy shown in brackets. a) 7765 (nearest hundred). b) 1099 (near

wlad13 [49]

Answer:

a. 700

b. 1000

c. 80

d. 700

e.

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1 year ago

Which table has a constant of proportionality between y and x of 12?

Nikolay [14]

Answer & Step-by-step explanation:

To find if they have a constant of proportionality of 12, use the following:

$\frac{y}{x}=12$

Divide y by the x value (x,y), and if the remaining equation is true, then that table has a constant of proportionality of 12.*

:Done

*Make sure you check all the values in a table. Sometimes only the first values will have k=12, while the others don't.

**The constant of proportionality is represented by <em>k</em>.

3 0

3 years ago

Read 2 more answers

On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove

gogolik [260]

Velocity, distance and time:

This question is solved using the following formula:

$v = \frac{d}{t}$

In which v is the velocity, d is the distance, and t is the time.

On the first day of travel, a driver was going at a speed of 40 mph.

Time $t_1$ , distance of $d_1$ , v = 40. So

$v = \frac{d}{t}$

$40 = \frac{d_1}{t_1}$

The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles

On the second day, the velocity is $v = 60$ .

On the first day, he drove 2 more hours, which means that for the second day, the time is: $t_1 - 2$

On the first day, he traveled 20 more miles, which means that for the second day, the distance is: $d_1 - 20$

Thus

$v = \frac{d}{t}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

System of equations:

Now, from the two equations, a system of equations can be built. So

$40 = \frac{d_1}{t_1}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

Find the total distance traveled in the two days:

We solve the system of equation for $d_1$ , which gets the distance on the first day. The distance on the second day is $d_2 = d_1 - 20$ , and the total distance is:

$T = d_1 + d_2 = d_1 + d_1 - 20 = 2d_1 - 20$

From the first equation:

$d_1 = 40t_1$

$t_1 = \frac{d_1}{40}$

Replacing in the second equation:

$60 = \frac{d_1 - 20}{t_1 - 2}$

$d_1 - 20 = 60t_1 - 120$

$d_1 - 20 = 60\frac{d_1}{40} - 120$

$d_1 = \frac{3d_1}{2} - 100$

$d_1 - \frac{3d_1}{2} = -100$

$-\frac{d_1}{2} = -100$

$\frac{d_1}{2} = 100$

$d_1 = 200$

Thus, the total distance is:

$T = 2d_1 - 20 = 2(200) - 20 = 400 - 20 = 380$

The total distance traveled in two days was of 380 miles.

For the relation between velocity, distance and time, you can take a look here: brainly.com/question/14307500

3 0

3 years ago