Question

PLEASE HELP FAST!!!!

Answer 1

We have been given that the formula for the force of gravity pulling on the bob is given by $F=m\times g\times sin(\theta)$), where g is equal to$9.8m/s^2$.

Now, we have been given that the mass of the bob of the pendulum is 0.01 kg and that the pendulum makes 22.5 degree angle with the vertical.

Thus, applying the given values in the formula of the given in the question, we get the formula to be:

$F=m\times g\times sin(\theta)=0.01\times9.8\times sin(22.5^{\circ})$

$\therefore F\approx0.0375$ N

Answer 2

The force would be 0.04.

This is found by using the formula:

F=mg sinθ
F = 0.01(9.8)sin (22.5)
F ≈ 0.04