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Tju [1.3M]
3 years ago
9

Heather is trying to decrease the amount of toys that Oliver has. Originally, he had 55 toys in his room and now he only has 30.

By what percentage did Heather decrease the amount of toys?
Mathematics
2 answers:
diamong [38]3 years ago
5 0
25/55 = x/100, so I think it is 45% Decreased.
Svetradugi [14.3K]3 years ago
3 0

Answer:  45.45%

Step-by-step explanation:

Given:  The number of toys in Heather's room before = 55

The number of toys now in the room = 30

Now, the decrease in the toys = 55-30=25

We know that the percent decrease is given by ;-

\dfrac{\text{Decrease in amount}}{\text{amount before}}\times100

\\=\dfrac{25}{55}\times100=45.4545\approx45.45\%

Hence, Heather decrease the amount of toys by  45.45% .

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nadya68 [22]

Answer: (US$ 38.00) + 80% =

68.4 US$

Step-by-step explanation:

6 0
3 years ago
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3.16 SAT scores: SAT scores (out of 2400) are distributed normally with a mean of 1490 and a standard deviation of 295. Suppose
AURORKA [14]

Answer:

0.2333 = 23.33% probability this student's score will be at least 2100.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution, and conditional probability.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

SAT scores (out of 2400) are distributed normally with a mean of 1490 and a standard deviation of 295.

This means that \mu = 1490, \sigma = 295

In this question:

Event A: Student was recognized.

Event B: Student scored at least 2100.

Probability of a student being recognized:

Probability of scoring at least 1900, which is 1 subtracted by the pvalue of Z when X = 1900. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{1900 - 1490}{295}

Z = 1.39

Z = 1.39 has a pvalue of 0.9177

1 - 0.9177 = 0.0823

This means that P(A) = 0.0823

Probability of a student being recognized and scoring at least 2100:

Intersection between at least 1900 and at least 2100 is at least 2100, so this is 1 subtracted by the pvalue of Z when X = 2100.

Z = \frac{X - \mu}{\sigma}

Z = \frac{2100 - 1490}{295}

Z = 2.07

Z = 2.07 has a pvalue of 0.9808

This means that P(A \cap B) = 1 - 0.9808 = 0.0192

What is the probability this student's score will be at least 2100?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0192}{0.0823} = 0.2333

0.2333 = 23.33% probability this student's score will be at least 2100.

4 0
3 years ago
What is the value of the remainder if 10x^4 – 6x^3 + 5x^2 – x + 1 is divided by x – 3?
ludmilkaskok [199]

Answer: 691

<u>Step-by-step explanation:</u>

There are 3 different ways to find the remainder.  I am not sure which method you are supposed to use, so I will solve using all 3 methods.

Long Division:

       <u>  10x³ + 24x² + 77x + 230 </u>

x - 3 ) 10x⁴ -  6x³  + 5x²   - x  +  1

      - <u>(10x⁴ - 30x³) </u>   ↓       ↓      ↓

                   24x³ + 5x²     ↓      ↓

               - <u>(24x³ - 72x²) </u>   ↓      ↓

                              77x²  - x       ↓

                         -  <u>(77x² - 231x) </u>  ↓

                                        230x + 1

                                     - <u>(230x - 690)</u>

                                                    691 ← remainder

Synthetic Division:

x - 3 = 0   ⇒  x = 3

3  |  10     -6        5       -1        1

   |<u>   ↓      30     72    231    690</u>

      10      24     77    230   691 ← remainder

Remainder Theorem:

f(x) = 10x⁴ - 6x³ + 5x²  - x  +  1

f(3) = 10(3)⁴ - 6(3)³ + 5(3)² - (3)  +  1

     =  810   - 162    + 45    -  3  +  1

     = 691

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Recall that using the pythaogorean theorem, which is only for right-triangles, the longest leg squared is the sum of the other two squared, namely c² = a² + b², now, if those units above are of a right triangle, then 25² = 7² + 24².

do they check out? if they do, then yes, you can make a right-triangle, if not, they nope.
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3 years ago
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