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zzz [600]
3 years ago
8

What is the end behavior of the graph of the exponential function f(x)=b^x when 0

Mathematics
2 answers:
Crazy boy [7]3 years ago
8 0

The diagram shows the graph of the function f(x)=b^x.

This graph is increasing, when b>1 and decreasing, when 0<b<1.

From this graph (in case 0<b<1) you can see that

  • f(x)\to \infty, when x\to -\infty;
  • f(x)\to 0, when x\to \infty.

Answer: correct option B.


sashaice [31]3 years ago
8 0

Answer:

b)f(x) -->0, when x --->∞ and f(x)--->∞, when x--->-∞

Step-by-step explanation:

First let's draw the graph.

Here f(x) = b^x, when 0 < b < 1

Here b greater than zero and less than 1.

Therefore, b must be number which is less 1 and greater 0.

Let's take b = 1/2 and the function becomes f(x) = (1/2)^x

Now let's draw the graph to find the answer.

In the graph,

f(x) -->0, when x --->∞ and f(x)--->∞, when x--->-∞

Therefore, answer is b)f(x) -->0, when x --->∞ and f(x)--->∞, when x--->-∞

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n200080 [17]
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3 0
3 years ago
Find the slope of the line through each pair of points (2, -11), (7, -20)
baherus [9]
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5 0
2 years ago
Please help me solve this problem
Alla [95]

Answer:

Option B , D and E are correct.

Step-by-step explanation:

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So, if 3 is in the division box then the denominator will be

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So, Option E is correct

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because after division the result given is 2x+4 which is correct.

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8 0
3 years ago
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kobusy [5.1K]
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|3x - 2| = 16
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3 years ago
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= 398.24

Hope this helps :) have a great day/ night!!!!!!

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