Okay well, if you make a graph, Point A (7,0) and Point B (4,6) are in the top right quadrant. and Point C (1,1) and Point D (5,3) are in the top left, top right, and bottom left quadrant (I'll link a photo of the graph.)
so the lines intersect and make it perpendicular
Answer:
46.5
Step-by-step explanation:
Of all straight angles have 180 degrees in them.
So, to find x we need to form this equation:
x + 65 + x - 22 = 180
2x + 43 = 180
2x = 180-43
2x = 137
68.5 degrees = x
68.5-22 = 46.5 degrees.
m<CBD = 46.5 degrees.
m<GBF = also 46.5 degrees because it is a vertical angle to <46.5 degrees.
-8 is the answer ........
7) -5-x=0
x=-5
8) 4x-36=0
4(x-9)=0
x-9=0
x=9
If you use this equation then you say that the ground is h=0 and solve as a quadratic.
The quadratic formula is (-b±<span>√(b^2-4ac))/2a when an equation is in the form ax^2 + bx + c
So the equation you have been given would be -16t^2-15t-151 = 0
This equation has no real roots which leads me to believe it is incorrect.
This is probably where your difficulty is coming from, it's a mistake.
The equation is formed from S=ut+(1/2)at^2+(So) where (So) is the initial height and S is the height that you want to find.
In this case you want S = 0.
If the initial height is +151 and the initial velocity and acceleration are downwards (negative) and the initial velocity (u) is -15 and the initial acceleration is -32 then you get the equation S=-15t-16t^2+151
Solving this using the quadratic formula gives you t = 2.64 or t = -3.58
Obviously -3.58s can't be the answer so you're left with 2.64 seconds.
Hope this makes sense.
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