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Nesterboy [21]
3 years ago
15

The length of a rectangle is 16 inches longer than its width. if the perimeter of the rectangle is is 540 inches, what is the le

ngth in inches
Mathematics
2 answers:
creativ13 [48]3 years ago
6 0
Try by using the 5-D process
ludmilkaskok [199]3 years ago
4 0
W=width, W+16=length
2w + 2(w+16) = 540in
2w + 2w + 32 = 540in
Subtract 32 from both sides
Combine like with like
4w = 508in
Divide by 4 on both sides
W=127in.
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(-2,-1)

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5 0
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Simplify so it's in slope-intercept form (y=mx+b)<br><br> y - 125 = 55(x - 2)
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y = 55x + 15

Step-by-step explanation:

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4 0
3 years ago
Write an equation that represents the following statement. Five less than the product of r and two is 3.
liraira [26]
Your equation should be 5 - r + 2 = 3.
4 0
2 years ago
What is the correct slope intercept form of the equation y + 16 = 3(x - 0) ?
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8 0
3 years ago
Suppose that we want to test the hypothesis with a significance level (alpha) of .05 that the climate has changed since industri
saw5 [17]

Answer: we reject the initial claim

(50. 3802, 51.6198)

Step-by-step explanation:

A)

The initial statement is that the mean temperature throughout history is 50°

This is the null hypothesis and it is denoted as H'

H': u = 50.

After taking a sample of 40 years, we realized that the mean temperature is 51°.

This is the alternative hypothesis, in contradiction to the alternative.

The alternative hypothesis is denoted as H1

H1: u > 50 ( upper tailed).

Sample size (n) = 40

Sample mean (x) = 51

Population standard deviation (σ) = 2

We use a z test to get the value of the test statistics.

We are using a z test because sample size is greater than 30 ( n = 40) and population standard deviation is given.

Z score = x - u/ (σ/√n)

Z score = 51 - 50 / (2/√40)

Z score = 1 / 0.3162

Z score = 3.16

Our level of significance is 5%, and the critical value at this level of significance is 1.645.

By comparing the z score relative to the critical value, since our z score is greater than 1.645, it implies that we are in the rejection region hence we reject the initial claim.

B)

We are to construct a 95% confidence interval for population mean temperature.

For upper limit

u = x + Zα/2 ×(σ/√n)

Where Zα/2 = 1.96 which is the critical value for a two tailed test at 5% level of significance.

For upper limit, we have that

u = 51 + 1.96 × (2/√40)

u = 51 + 1.96 (0.3162)

u = 51 + 0.6198

u = 51.6198.

For lower limit, we have that

u = 51 - 1.96 × (2/√40)

u = 51 - 1.96 (0.3162)

u = 51 - 0.6198

u = 50. 3802.

Hence the 95% confidence level for mean temperature is given as (50. 3802°, 51.6198°)

7 0
3 years ago
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