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Nesterboy [21]
3 years ago
15

The length of a rectangle is 16 inches longer than its width. if the perimeter of the rectangle is is 540 inches, what is the le

ngth in inches
Mathematics
2 answers:
creativ13 [48]3 years ago
6 0
Try by using the 5-D process
ludmilkaskok [199]3 years ago
4 0
W=width, W+16=length
2w + 2(w+16) = 540in
2w + 2w + 32 = 540in
Subtract 32 from both sides
Combine like with like
4w = 508in
Divide by 4 on both sides
W=127in.
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Answer:

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Step-by-step explanation:

We are given that M is the midpoint of CD and that C = (10, -5) and M = (4, 0).

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Recall that the midpoint is given by:

\displaystyle M = \left(\frac{x_1 + x_2}{2} , \frac{y_1 + y_2}{2}\right)

Let C(10, -5) be (<em>x</em>₁<em>, y</em>₁) and Point D be (<em>x</em>₂<em>, y</em>₂). The midpoint M is (4, 0). Hence:

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This yields two equations:

\displaystyle \frac{x_2 + 10}{2} = 4\text{ and } \frac{y_2 - 5}{2} = 0

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\displaystyle \begin{aligned}x_2 + 10 &= 8 \\ x_2 &= -2 \end{aligned}

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In conclusion, Point<em> </em>D = (-2, 5).

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