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Nesterboy [21]
3 years ago
15

The length of a rectangle is 16 inches longer than its width. if the perimeter of the rectangle is is 540 inches, what is the le

ngth in inches
Mathematics
2 answers:
creativ13 [48]3 years ago
6 0
Try by using the 5-D process
ludmilkaskok [199]3 years ago
4 0
W=width, W+16=length
2w + 2(w+16) = 540in
2w + 2w + 32 = 540in
Subtract 32 from both sides
Combine like with like
4w = 508in
Divide by 4 on both sides
W=127in.
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Find the perimeter of WXYZ. Round to the nearest tenth if necessary.
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Answer:

C. 15.6

Step-by-step explanation:

Perimeter of WXYZ = WX + XY + YZ + ZW

Use the distance formula, d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} to calculate the length of each segment.

✔️Distance between W(-1, 1) and X(1, 2):

Let,

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WX = 2.24

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Let,

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Y(2, -4) = (x_2, y_2)

Plug in the values

XY = \sqrt{(2 - 1)^2 + (-4 - 2)^2}

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Let,

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Let,

Z(-2, -1) = (x_1, y_1)

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Plug in the values

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✅Perimeter = 2.24 + 6.08 + 5 + 2.24 = 15.56

≈ 15.6

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