A (n + y) = 10y + 32
(an + ay) = 10y + 32
an + ay = 32 + 10y
Solve for "a"
-32 + an + ay + (-10y) = 32 + 10y + (-32) + (-10y)
-32 + an + ay + -10y = 32 + -32 + 10y + -10y
<span>- 32 + an + ay + (-10y) = 0 + 10y + (-10y)
- 32 + an + ay + (-10y) = 10y + (-10y)
</span><span>10y + -10y = 0
-32 + an + ay + (-10y) = 0
Thi could not be determined. (no solution)</span>
I think associative property of addition
Micheal has 40ft of fencing for the rectangular dog run. So the perimeter of the dog run is 40ft.
Perimeter=40ft
The perimeter of a rectangle is:
P=2l+2w
Since we know the length is 5 and the perimeter is 40, we can solve for the width.
P=2l+2w
40=2*(5)+2w
40=10+2w
subtract 10 from both sides
30=2w
divide both sides by 2
15=w
The width of the fence is 15feet.
The function that is graphed is...
B.) y = |x - 3| - 4
Since the lines "|" in the function make it a V shape.
And when you graph the one point where the the 2 lines meet it is.
(-3, -4)
So this answer is correct. :P
Good Luck! :)
