27a-(3b-(2a-(4a-c)+6a (2a+3b-c)
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Given:
Image of the ellipse
To find:
The equation of the image
Solution:
The given image is a ellipse.
Center of the ellipse = (0, 0)
x-axis points are (-3, 0) and (3, 0).
y-axis points are (2, 0) and (-2, 0).
Standard form of equation of ellipse:
where (h, k) is the center = (0,0)
a is the point on x-axis where y = 0. Hence a = 3.
b is the point on y-axis where x = 0. Hence b = 2.
Substitute this in the standard form of ellipse.
To make the denominator same multiply 1st term by and 2nd term by
.
Multiply by 36 on both sides
The equation of the image is .