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rodikova [14]
3 years ago
10

Please help with number one through 8 and please answer cause I waste 10 points to post this question so u people can help me so

please help me thanks !! HELP PLEASE I AM DYING JK BUT I NEED HELP PLEASE !!

Mathematics
1 answer:
Taya2010 [7]3 years ago
7 0
On row 1, E is the wrong one because it should be 9n but its 8n instead
On row 2, P is the wrong one because it should be 6x but its 6+3x instead
On row 3, N is the wrong one because it should be 2x+2 but its 3x instead
On row 4, R is the wrong on because it should be 11a+3 but its 14a instead
On row 5, R is the wrong one because it should be 18n but its 9n instead
On row 6, M is the wrong one because it should be 15x+3 but its 15x+45 instead
On row 7, A is the wrong one because it should be 14t+4 but its 18t instead
On row 8, E is the wrong one because it should be 3n+21 but its 9+7n
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Cos ( α ) = √ 6/ 6 and sin ( β ) = √ 2/4 . Find tan ( α − β )
Zina [86]

Answer:

\purple{ \bold{ \tan( \alpha  -  \beta ) = 1.00701798}}

Step-by-step explanation:

\cos( \alpha ) =  \frac{ \sqrt{6} }{6}  =  \frac{1}{ \sqrt{6} }  \\  \\  \therefore \:  \sin( \alpha )  =  \sqrt{1 -  { \cos}^{2} ( \alpha ) }  \\  \\  =  \sqrt{1 -  \bigg( {\frac{1}{ \sqrt{6} } \bigg )}^{2} }  \\  \\ =  \sqrt{1 -  {\frac{1}{ {6} }}}  \\  \\ =  \sqrt{ {\frac{6 - 1}{ {6} }}}   \\  \\  \red{\sin( \alpha ) =  \sqrt{ { \frac{5}{ {6} }}} } \\  \\  \tan( \alpha ) =  \frac{\sin( \alpha ) }{\cos( \alpha ) }  =  \sqrt{5}  \\  \\ \sin( \beta )  =  \frac{ \sqrt{2} }{4}  \\  \\  \implies \: \cos( \beta )  =   \sqrt{ \frac{7}{8} }  \\  \\ \tan( \beta )  =  \frac{\sin( \beta ) }{\cos( \beta ) } =  \frac{1}{ \sqrt{7} }   \\  \\  \tan( \alpha  -  \beta ) =  \frac{ \tan \alpha  -  \tan \beta }{1 +  \tan \alpha .  \tan \beta}  \\  \\  =  \frac{ \sqrt{5} -  \frac{1}{ \sqrt{7} }  }{1 +  \sqrt{5} . \frac{1}{ \sqrt{7} } }  \\  \\  =  \frac{ \sqrt{35} - 1 }{ \sqrt{7}  +  \sqrt{5} }  \\  \\  \purple{ \bold{ \tan( \alpha  -  \beta ) = 1.00701798}}

8 0
3 years ago
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baherus [9]

Answer: 77

Step-by-step explanation:

3 0
2 years ago
A fraction where the numerator is smaller than the denominator
Anit [1.1K]

Answer:

Step-by-step explanation:

A fraction where the numerator is smaller than the denominator is called proper fraction e.g 2/3,4/7 etc

8 0
3 years ago
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lana66690 [7]
Your answer would be 2
7 0
3 years ago
What method would you choose to solve the equation 2x2 – 7 = 9? Explain why you chose this method.
Kisachek [45]
<span>This is a quadratic equation . We order to equate to zero

</span>2x²<span> – 7 = 9  
 </span>
2x² - 7-9 = 0
2x² - 16 = 0

This equation is a binomial
2* (x² - 8) = 0
<span>We choose the simplest method . The equation with practice it can be calculated in the memory
</span><span>
The product is equal to 0 if one of the factors is zero
</span>
2≠0  ∨     x² - 8 = 0
               x² = √8
               x = √8     ∨  x= - √8

Answer : x = √8 ∨ x = -√8
5 0
3 years ago
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