Answer:
See below.
Step-by-step explanation:
Draw segment OB.
In triangle OBC, points R and S are the midpoints of sides OC and BC, respectively. That makes RS parallel to OB.
In triangle OBA, points P and Q are the midpoints of sides OA and BA, respectively. That makes PQ parallel to OB.
Since segments RS and PQ are parallel to segment OB, then RS and PQ are parallel to each other.
Answer:
Height of tree is
<em>15 m.</em>
<em></em>
Step-by-step explanation:
Given that student is 20 m away from the foot of tree.
and table is 1.5 m above the ground.
The angle of elevation is: 34°28'
Please refer to the attached image. The given situation can be mapped to a right angled triangle as shown in the image.
AB = CP = 20 m
CA = PB = 1.5 m
= 34°28' = 34.46°
To find TB = ?
we can use trigonometric function tangent to find TP in right angled 

Now, adding PB to TP will give us the height of tree, TB
Now, height of tree TB = TP + PB
TB = 13.72 + 1.5 = 15.22
<em>15 m</em>
Answer:
Sum of two interior angles=exterior angle




Done!
Answer:
-16
Step-by-step explanation:
m^2 + n^2
-5^2 + 3^2 = -16