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tigry1 [53]
3 years ago
5

If y varies directly as x and y = 21 when x = 5, find x when y = 42.

Mathematics
1 answer:
Lorico [155]3 years ago
5 0

Answer: 10

<u>Step-by-step explanation:</u>

varies directly means: \frac{y}{x} = k

Step 1: solve for k   ⇒  \frac{21}{5} = k

Step 2: plug in the given value and k to solve for the missing value: \frac{42}{x} = \frac{21}{5}

42(5) = 21(x)

\frac{42(5)}{21} = \frac{21(x)}{21}

2(5) = x

10  = x


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R, S, Q and P are the midpoints of OC, CB, BA and OA respectively.
Stolb23 [73]

Answer:

See below.

Step-by-step explanation:

Draw segment OB.

In triangle OBC, points R and S are the midpoints of sides OC and BC, respectively. That makes RS parallel to OB.

In triangle OBA, points P and Q are the midpoints of sides OA and BA, respectively. That makes PQ parallel to OB.

Since segments RS and PQ are parallel to segment OB, then RS and PQ are parallel to each other.

3 0
2 years ago
A student stands 20 m away from the foot
Ostrovityanka [42]

Answer:

Height of tree is \approx <em>15 m.</em>

<em></em>

Step-by-step explanation:

Given that student is 20 m away from the foot of tree.

and table is 1.5 m above the ground.

The angle of elevation is: 34°28'

Please refer to the attached image. The given situation can be mapped to a right angled triangle as shown in the image.

AB = CP = 20 m

CA = PB = 1.5 m

\angle C = 34°28' = 34.46°

To find TB = ?

we can use trigonometric function tangent to find TP in right angled \triangle TPC

tan \theta = \dfrac{Perpendicular}{Base}\\tan C= \dfrac{PT}{PC}\\\Rightarrow tan 34.46^\circ = \dfrac{PT}{20}\\\Rightarrow PT = 20 \times 0.686 \\\Rightarrow PT = 13.72\ m

Now, adding PB to TP will give us the height of tree, TB

Now, height of tree TB = TP + PB

TB = 13.72 + 1.5 = 15.22 \approx <em>15 m</em>

7 0
3 years ago
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Alja [10]

Answer:

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\\ \sf\longmapsto 4x+17=7x-1

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Done!

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Neko [114]
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3 years ago
Consider this expression.
USPshnik [31]

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5 0
1 year ago
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