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Kay [80]
3 years ago
5

Find the value of log 1.0125

Mathematics
1 answer:
Volgvan3 years ago
3 0
The answer is 0.00539503188


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Help me i need to submit to my teacher by 8pm​
Vladimir [108]

Please see the figure. We'll first work out half the area of the rounded triangle, half the unshaded part, then double it, then subtract it from the big square.

Half the area is the circular sector PTQ (with center P, arc TQ) minus the right triangle PUT.

A/2 = area(sector PTQ) - area(triangle PUT)

The triangle is half of equilateral triangle PQT, so a 30/60/90 right triangle so we know the sides are in ratio 1:√3:2 so

TU = (7/2)√3

area(PUT) = (1/2) (7/2)(7/2)√3 = (49/8)√3

area(sector PTQ) = (angle TQP / 360°) πr^2

We know angle TQP is 60° because TQP is equilateral.  r=7.

area(sector PTQ) = (60°/360°) π (7²) = 49π/6

Putting it together,

A/2 = area(sector PTQ) - area(triangle PUT)

A = 2(49π/6 -  (49/8)√3)

A = 49(π/3 - √3/4) square cm

I hate ruining a nice exact answer with an approximation, but they seem to be asking.

A ≈ 30.095057615914535

Check:

I'm not sure how to check it.  I'd estimate it's about 25% bigger than equilateral triangle PQT with area (√3/4)7² ≈ 21.2, so around 27. 30 seems reasonable.

Now the real area we seek is the big square PQRS minus A, so

area = 7² - 30.095057615914535 = 18.904942384086 sq cm

They want square meters for some reason; we scale by (1/100)²

Answer: 0.00189 square meters

7 0
3 years ago
Determine from the following(choice one or choice two) mapping is a Function. Choice One Choice Two 3 1 0 2 3 2 -1 3 2 3 -2 0 Ex
saul85 [17]

Answer:

3 is a function because it is repeating and 2 is reapting to

Step-by-step explanation:

4 0
2 years ago
Please help meeee<br><br><br>I need helpppp​
xz_007 [3.2K]

Answer:

the slope is 5 i do y feel like doing the work buuut ik im right mark me as brainlyest if im right

7 0
2 years ago
Read 2 more answers
In circle E, AC=4, CG=6, and AH=3, Find HB and EG. If necessary, round to the tenths place.
bezimeni [28]
Using theorem about secant segments we can write,
AB*AH=AG*AC
AC=4,
CG=6
AG=AC+CG=4+6=10
AH=3
AB= AH+HB=AH+x=3+x
(3+x)*3=10*4
9+3x=40
3x=40-9
3x=31
x=31/3≈10.3
HB≈10.3
EG=HB/2 (as radius and diameter)
EG=10.3/2≈5.2




3 0
3 years ago
Use the number 145,973 write the name of the period that has the digits 145
Alexeev081 [22]
145,973 Is decimaled in 145.
14.5
1.45
.145
7 0
3 years ago
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