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qaws [65]
3 years ago
6

When segments intersect inside a circle, what is the relationship between the angle of intersection and the intercepted arcs?

Mathematics
2 answers:
n200080 [17]3 years ago
7 0

Answer:

Supplementary

Step-by-step explanation:

They would have to form 180 degrees

boyakko [2]3 years ago
4 0
THERE HAVE ALOT OF RELATIONSHIP 

It'll be clearer if you are spefic by giving a sketch of what you mean. 

1). if their angle of intersection is 90 degrees, then the arcs where sustended by the diameter of the circle 

2). the angle of intersection of the segments is equal but opposite to the angle of the intersected arcs which is directly proportional to the lengths of the arcs. 

<span>3). If the intersection occurs at the centre of the circle, the length of the arc produced is a function of the radius of the circle. 



I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!</span>
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3c-d=T<br> Could you<br> solve for c
RSB [31]
- - Let's solve for C.

Starting off with our equation:
3c+d=T

Transform:
3c=T+D

Solve for that:
\frac{3c}{3} = \frac{T+D}{3}


Solve for that for the last time and your answer is \frac{T+D}{3} =C



7 0
2 years ago
Read 2 more answers
If a positive integer is equal to the following product: 25b3c425b3c4, where b and c are distinct prime numbers greater than 2,
Vlad [161]

Answer: 64 distinct even factors

Step-by-step explanation:

let the 2 distinct numbers be b and c and the integer is expected to be 25b3c425b3c4

since b, c > 2 and prime numbers,

potential options include 3, 5, and 7

hence the likelihoods are (b = 3, c = 5), (b = 5, c = 3), (b = 3, c = 7), (b = 7, c = 3), (b = 5, c = 7), (b = 7, c = 5)

Possibility 1 (b = 3, c = 5)

integer is now 253354253354

the distinct even factors = 2, 202, 262, 1934, 19802, 26462, 195334, 253354, 2000002, 2594062, 19148534, 25588754, 262000262, 1934001934, 2508457954, 253354253354

number of distinct even factors = 16

Possibility 2 (b = 5, c = 3)

integer is now 255334255334

the distinct even factors = 2, 86, 202, 5938, 8686, 19802, 253354, 599738, 851486, 2000002, 25788734, 58792138, 25588754, 86000086, 2528061934, 1934001934, 5938005938, 253354253354

number of distinct even factors = 18

Possibility 3 (b = 3, c = 7)

integer is now 253374253374

the distinct even factors = 2, 6, 22, 66, 202, 242, 606, 698, 726, 2094, 2222, 6666, 7678, 19802, 23034, 24442, 59406, 70498, 73326, 84458, 211494, 217822, 253374, 653466, 775478, 2000002, 2326434, 2396042, 6000006, 6910898, 7188126, 8530258, 20732694, 22000022, 25590774, 66000066, 76019878, 228059634, 242000242, 698000698, 726000726, 836218658, 2094002094, 2508655974, 7678007678, 23034023034, 84458084458,253354253354

number of distinct even factors = 48

Possibility 4 (b = 7, c = 3)

integer is now 257334257334

the distinct even factors = 2, 6, 14, 22, 42, 66, 154, 202, 462, 606, 1114, 1414, 2222, 3342, 4242, 6666, 7798, 12254, 15554, 19802, 23394, 36762, 46662, 59406, 85778, 112514, 138614, 217822, 257334, 337542, 415842, 653466, 787598, 1237654, 1524754, 2000002, 2362794, 3712962, 4574262, 6000006, 8663578, 11029714, 14000014, 22000022, 25990734, 33089142, 42000042, 66000066, 77207998, 121326854, 154000154, 231623994, 363980562, 462000462, 849287978, 1114001114, 2547863934, 3342003342, 7798007798, 12254012254, 23394023394, 36762036762, 85778085778, 257334257334

number of distinct even factors = 64

Possibility 5 (b = 5, c = 7)

integer is now 255374255374

the distinct even factors = 2, 14, 34, 58, 74, 202, 238, 406, 518, 986, 1258, 1414, 2146, 3434, 5858, 6902, 7474, 8806, 15022, 19802, 24038, 36482, 41006, 52318, 99586, 127058, 138614, 216746, 255374, 336634, 574258, 697102, 732674, 889406, 1517222, 2000002, 2356438, 3684682, 4019806, 5128718, 9762386, 12455458, 14000014, 21247546, 25792774, 34000034, 58000058, 68336702, 74000074, 87188206, 148732822, 238000238, 361208282, 406000406, 518000518, 986000986, 1258001258, 2146002146, 2528457974, 6902006902, 8806008806, 15022015022, 36482036482, 255374255374

number of distinct even factors = 64

Possibility 6 (b = 7, c = 5)

integer is now 257354257354

the distinct even factors = 2, 202, 19802, 257354, 2000002, 25992754, 2548061954, 257354257354

number of distinct even factors = 8

From the six possibilities, the highest number of likely distinct even factors is 64

7 0
3 years ago
Find the slope of the line that contains (−3,5) and (3,−9).
snow_lady [41]
The slope is this and that
5 0
3 years ago
The equation the quantity 2x minus 20 divided by 3 = 2x models temperature change, where x represents the difference in degrees
irina [24]

The solution to the equation is x = -5

<h3>How to determine the value of x?</h3>

The equation is given as:

the quantity 2x minus 20 divided by 3 = 2x

Rewrite properly as

(2x - 20)/3 = 2x

Multiply through by 3

2x - 20 = 6x

Collect like terms

6x - 2x = -20

This gives

4x = -20

Divide by 4

x = -5

Hence, the solution to the equation is x = -5

Read more about equations at:

brainly.com/question/13763238

#SPJ1

5 0
1 year ago
Steel Factory Workers Ages
igor_vitrenko [27]

Solution: We are given the population mean =42

Now, in order to find which shift's mean is closest to population mean, we will find the mean of each shift.

The mean of shift 1 is:

Mean=\frac{18+25+56+42+29+38+54+47+35+30}{10}=\frac{374}{10}=37.4

The mean of shift 2 is:

Mean=\frac{23+19+50+49+67+34+30+59+40+33&#10;}{10}=\frac{404}{10}=40.4

The mean of shift 3 is:

Mean=\frac{19+22+24+40+45+29+33+29+39+59  }{10}=\frac{339}{10}=33.9

The mean of shift 4 is:

Mean=\frac{21+23+25+40+35+19+70+40+22+23  }{10}=\frac{318}{10}=31.8

We clearly see the mean of shift 2 is close to the population mean. Hence the option B) Shift 2 is correct.

7 0
3 years ago
Read 2 more answers
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