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omeli [17]
3 years ago
11

If B is the midpoint of AC, AC=CD, AB=3x+4, AC=11x-17, and CE=49, find DE.

Mathematics
1 answer:
Luba_88 [7]3 years ago
6 0

Answer:

11

Step-by-step explanation:

AB = 3x + 4 and AC which is twice of AB is equal to 11x - 17

2 (3x + 4) = 11x - 17

6x + 8 = 11x - 17

8 + 17 = 11x - 6x

25 = 5x

5 = x

AC = CD = 11x - 17 ➡ 11×5 - 17 = 38

CD = 38 and DE = 49 - 38 = 11

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Answer:

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Step-by-step explanation:

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Rewriting

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3 years ago
I need the answers and explanation to a b c and d
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Answer:

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The second attachment shows a graph of the four inequalities with their shading.

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<em>Additional comment</em>

All of the inequalities are written in standard form, so the x-coefficient is positive for all of them. The direction of the inequality symbol can be chosen to select values of x that are greater than or less than those on the boundary line. If the shading is to be to the right, then larger x-values are required, and the inequality will have the form ax + by ≥ c (a > 0). If shading is to the left, then smaller x-values are required, and the inequality symbol points in the other direction.

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