Answer: Children tickets cost 7.50
Adult tickets cost 12.50
Step-by-step explanation:
Let a represent adult tickets
Let c represent child tickets
On the first day she sells 6 adult tickets and 5 children tickets for total of 112.50. This can be written as:
6a + 5c = 112.50 ...... equation i
On the second day she sells 8 adult tickets and 4 children tickets for the total 130. This can be written as:
8a + 4c = 130 ....... equation ii
6a + 5c = 112.50 ...... equation i
8a + 4c = 130 ....... equation ii
Multiply equation i by 4
Multiply equation ii by 5
24a + 20c = 450 ........ equation iii
40a + 20c = 650 ......... equation iv
Subtract iii from iv
16a = 200
a = 200/16
a = 12.50
Adult tickets cost 12.50
From equation ii,
8a + 4c = 130
8(12.50) + 4c = 130
100 + 4c = 130
4c = 130 - 100
4c = 30
c = 30/4
c = 7.50
Children tickets cost 7.50
she can count the number of row and the number of square in each row, or she can add 6 and 8
Answer:
Step-by-step explanation:
(x^4 + 2x^3 - 7x - 9) +
(x^5 - 2x^4 + 8x + 18)
x^5 - x^4 + 2x^3 + x + 9
I believe y equals 4.
9/4y - 12. = 1/4y - 4
+ 12. +12
9/4y. = 1/4y + 8
- 1/4y. - 1/4y
8/4y. = 8
2y. = 8
2. 2
Y = 4
