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Naddik [55]
3 years ago
8

C++

Computers and Technology
1 answer:
kotegsom [21]3 years ago
8 0

Answer:

a) # include <iostream>

# include <conio.h>

# include <stdio.h>

# include <string.h>

using namespace::std;

bool IsPalindrome(const string& str)

{

   if (str.empty())

       return false;

   int i = 0;                // first characters

   int j = str.length() - 1; // last character

   while (i < j)

   {

     

       if (str[i] != str[j])

       {

           return false;

       }

       i++;

       j--;

   }

   return true;

}

int main()

{      

      string str;

      cout<<"Enter the string";

      getline(cin, str);

      bool a= IsPalindrome(str);

      if(a)

      {

          cout<<"Is in palindrome";

      }

      else

      {

          cout<<"Is not in palindrome";

      }

}

b) Modified version of function with full program to discard uppercase or lowercase is as below:

# include <iostream>

# include <conio.h>

# include <stdio.h>

# include <string.h>

using namespace::std;

bool IsPalindrome(const string& str)

{

   if (str.empty())

       return false;

   int i = 0;                // first characters

   int j = str.length() - 1; // last character

   while (i < j)

   {

       char a= tolower(str[i]);

       char b= tolower(str[j]);

       if (a != b)

       {

           return false;

       }

       i++;

       j--;

   }

   return true;

}

int main()

{      

      string str;

      cout<<"Enter the string";

      getline(cin, str);

      bool a= IsPalindrome(str);

      if(a)

      {

          cout<<"Is in palindrome";

      }

      else

      {

          cout<<"Is not in palindrome";

      }

}

Explanation:

Please check the answer section.

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Answer:

Step by step code along with explanation and output is given below

Explanation:

We can solve this problem using if elif else approach

def main():

# prompts the user to enter an integer from 1 to 10

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   print ('Roman Numeral for 1 is I')

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Answer:

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Explanation:

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