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zubka84 [21]
4 years ago
15

Calculate the profit or loss of Bing C., an accountant, with fees of $25,050 and expenses of $27,000.

Mathematics
1 answer:
Marrrta [24]4 years ago
7 0

Answer:

The amount decreases with negative value so, Losses occur and the loss amount is $ 1,950 .

Step-by-step explanation:

Given as :

The accountant fee amount = $ 25,050

The accountant expenses amount = $ 27,000

Now, Let The profit = P

And The loss = L

∵ expenses amount = $ 27,000   and  fee amount = $ 25,050

So, fee amount - expenses amount = $ 25,050 - $ 27,000  

I.e fee amount - expenses amount = - $ 1,950

As the amount decreases with negative value so, Losses occur

So, The loss amount = L = $ 1,950

Hence The amount decreases with negative value so, Losses occur and the loss amount is $ 1,950 . Answer

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Answer:

y = -x - 5

Step-by-step explanation:

The general structure of a line in slope-intercept form is:

y = mx + b

In this form, "m" represents the slope and "b" represents the y-intercept.

Since you have been given the slope and y-intercept, you can substitute these values into the equation to find the answer.

m = -1                  

b = -5

y = mx + b

y = (-1)x + (-5)

y = -x - 5

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2 years ago
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Answer:

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Step-by-step explanation:

7.5 + 82.5 equals 90°

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3 years ago
-2x-9y=-25<br> -4x-9y=-23<br><br> Solution -1,3
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3 years ago
Which choice lists the three lengths in order from greatest to least? A) 5.5, 32 , 5 B) 32 , 5.5, 5 C) 5, 5.5, 32 Eliminate D) 5
IgorLugansk [536]
It is B. 32, 5.5, 5
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4 0
3 years ago
Read 2 more answers
A. Find y in terms of x if
givi [52]

Answer:

A.y(x) =\sqrt{ 2(\frac{x^5}{5} -\frac{6^5}{5})}

B.Therefore the solution is defined on the interval:

6≤ x ≤ +∞

Step-by-step explanation:

Given differential equation is

\frac{dy}{dx} = x^4y^{-1}

\Rightarrow \frac{dy}{dx} =\frac{ x^4}{y}

\Rightarrow y dy = x^4dx

Integrating both sides:

\Rightarrow\int y dy = \int x^4dx

\Rightarrow \frac{y^2}{2} =\frac{x^5}{5} +C........(1)

Given y(0)= 6

it means y=0 when x=6

Putting x=6 and y=0 in the equation (1)

\therefore \frac{0^2}{2} =\frac{6^5}{5} +C

\Rightarrow C=-\frac{6^5}{5}

Equation (1) become:

\Rightarrow \frac{y^2}{2} =(\frac{x^5}{5} -\frac{6^5}{5})

\Rightarrow y} =\sqrt{ 2(\frac{x^5}{5} -\frac{6^5}{5})}

Therefore y(x) =\sqrt{ 2(\frac{x^5}{5} -\frac{6^5}{5})}

(B)

The quantity under root must greater than or equal to zero.

Therefore,

2(\frac{x^5}{5} -\frac{6^5}{5})} \geq0

\Rightarrow \frac{x^5}{5} -\frac{6^5}{5}} \geq0

\Rightarrow \frac{x^5}{5} \geq\frac{6^5}{5}}

\Rightarrow x^5\geq {6^5

\Rightarrow \sqrt[5]{x^5} \geq \sqrt[5]{6^5}

\Rightarrow x\geq {6

When x≥0 then the value of 2(\frac{x^5}{5} -\frac{6^5}{5})} is real other wise the value of 2(\frac{x^5}{5} -\frac{6^5}{5})} is imaginary.

Therefore the solution is defined on the interval:

6≤ x ≤ +∞

8 0
4 years ago
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