Think of A as a constant - with D it's 117 and with M it's 88
So the difference between D and M is 29 (117-88)
We also know that M + D = 161
Let's substitute in the problem We will leave M equal to M and rewrite D as M+29 since it is 29 kg heavier.
M + M + 29 -161 or 2M +29 = 161 Subtracting 29 from both sides we get 2M=122
Now divide both sides two and get M=61
Since D is M+29 it is 61+29 or 100kg
Finally A + M = 88 A + 61 - 88 Subtract 61 from both sides and get A=17
So there you have it:
A=17kg
M=61kg
D=100kg and it works in all three equation in your problem (try it to check)
There's many different types of shapes and figures. This is called <em>rhombus</em>.
A rhombus is a type of quadrilateral, and always has 4 sides and 4 verticals.
Answer:
(0,2)
Step-by-step explanation:
hey I guess I seen you before :-|
Answer:
A. the median of the lower half of a data set ordered from least to greatest
Step-by-step explanation:
The first quartile can best described as the median of the lower half of a data set ordered from least to greatest.
Let us explain this with an example, say you're given a set of numbers: {1, 2, 5, 8, 9, 12, 15, 16, 20, 23, 25, 28, 32, 36, 42}. The median for the set is 16, the first quartile is going to be the median of the first half which is 8.
