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3 years ago

7

The formula Q=MCT where Q=heat flow M=mass, C specfic heat, and T change of temperature is used to calculate heat flow Solve thi

s formula for t

2 answers:

BARSIC [14]3 years ago

6 0

Answer:

The formula for t is $T=\frac{Q}{MC}$

Step-by-step explanation:

Consider the provide formula.

$Q=MCT$

Where Q=heat flow M=mass, C specific heat, and T is the change of temperature is used to calculate heat flow.

We need to solve the above formula for T.

Divide both the sides by MC.

$\frac{Q}{MC}=\frac{MCT}{MC}$

$\frac{Q}{MC}=T$

$T=\frac{Q}{MC}$

Hence, the formula for t is $T=\frac{Q}{MC}$

Shtirlitz [24]3 years ago

3 0

Answer:

q/mc=t

Step-by-step explanation:

q=mct

q/mc=t

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Answer:

x = 1, y = 6

or

x = 5, y = 2.

Step-by-step explanation:

y=x2−7x+12

y=−x+7

Substitute for y in the first equation:

- x + 7 = x^2 - 7x + 12

x^2 - 7x + x + 12 - 7 = 0

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2 years ago

The length of a rectangular garden is three feet less than twice it’s width. If the perimeter of the garden is 42 feet, what is

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Answer:

The length of a rectangular garden is: 13 feet

Step-by-step explanation:

You have 2 lengths that are 2x-3 feet, and 2 widths that are x.

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4x -6 +2x -42 feet

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3 years ago

Indicate in standard form the equation of the line passing through the given points G (4,6) H (1,5)

Delicious77 [7]

First, find the slope (m) = $\frac{y2 - y1}{x2 - x1}$ = $\frac{5 - 6}{1 - 4}$ = $\frac{-1}{-3}$ = $\frac{1}{3}$

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3 years ago

ABC and EDC are straight lines. EA is parallel to DB. EC = 8.1 cm. DC = 5.4 cm. DB = 2.6 cm. (a) Work out the length of AE. cm (

harkovskaia [24]

By applying the knowledge of similar triangles, the lengths of AE and AB are:

a. $\mathbf{AE = 3.9 $ cm}\\\\$

b. $\mathbf{AB = 2.05 $ cm} \\\\$

<em>See the image in the attachment for the referred diagram.</em>

<em />

The two triangles, triangle AEC and triangle BDC are similar triangles.
Therefore, the ratio of the corresponding sides of triangles AEC and BDC will be the same.

<em>This implies that</em>:

AC/BC = EC/DC = AE/DB

<em><u>Given:</u></em>

$EC = 8.1 $ cm\\\\DC = 5.4 $ cm\\\\DB = 2.6 cm\\\\AC = 6.15 $ cm$

<u>a. </u><u>Find the length of </u><u>AE</u><u>:</u>

EC/DC = AE/DB

Plug in the values

$\frac{8.1}{5.4} = \frac{AE}{2.6}$

Cross multiply

$5.4 \times AE = 8.1 \times 2.6\\\\5.4 \times AE = 21.06$

Divide both sides by 5.4

$AE = \frac{21.06}{5.4} = 3.9 $ cm$

<u>b. </u><u>Find the length of </u><u>AB:</u>

$AB = AC - BC$

AC = 6.15 cm

To find BC, use AC/BC = EC/DC.

Plug in the values

$\frac{6.15}{BC} = \frac{8.1}{5.4}$

Cross multiply

$BC \times 8.1 = 6.15 \times 5.4\\\\BC = \frac{6.15 \times 5.4}{8.1} \\\\BC = 4.1$

Thus:

$AB = AC - BC$

Substitute

$AB = 6.15 - 4.1\\\\AB = 2.05 $ cm$

Therefore, by applying the knowledge of similar triangles, the lengths of AE and AB are:

a. $\mathbf{AE = 3.9 $ cm}\\\\$

b. $\mathbf{AB = 2.05 $ cm} \\\\$

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2 years ago

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sertanlavr [38]

Answer:

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Step-by-step explanation:

given functions are $f(x)=x-6$ and $g\left(x\right)=\frac{1}{2x\left(x+3\right)}$ .

Now we need to find about what is the value of $g\left(x\right)*f\left(x\right)$ .

$g\left(x\right)*f\left(x\right)$ simply means we need to multiply the value of $f(x)=x-6$ and $g\left(x\right)=\frac{1}{2x\left(x+3\right)}$ .

$g\left(x\right)\cdot f\left(x\right)=\frac{1}{2x\left(x+3\right)}\cdot\left(x-6\right)$

$g\left(x\right)\cdot f\left(x\right)=\frac{\left(x-6\right)}{2x\left(x+3\right)}$

Hence final answer is $g\left(x\right)\cdot f\left(x\right)=\frac{\left(x-6\right)}{2x\left(x+3\right)}$ .

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2 years ago