2 years ago

5X23X2 using properties to find the sum or product

Mathematics

1 answer:

lianna [129]2 years ago

4 0

$5\cdot 23 \cdot 2=(5\cdot 2)\cdot 23 = 10\cdot 23=230$

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2 years ago

What is the value of the remainder if 10x4 – 6x3 + 5x2 – x + 1 is divided by x – 3?

natita [175]

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Remainder is 691.

Step-by-step explanation:

Given function is $10x^4-6x^3+5x^2-x+1$ .

Now we need to find remainder if we divide given function $10x^4-6x^3+5x^2-x+1$ by (x-3)

(x-3) means plug x=3 into $10x^4-6x^3+5x^2-x+1$ to find remainder.

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$=10(3)^4-6(3)^3+5(3)^2-(3)+1$

$=10(81)-6(27)+5(9)-(3)+1$

$=810-162+45-3+1$

$=856-162-3$

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$=691$

Hence remainder is 691.

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