Answer:
The given functions are


The sine function has a standard period of
by definition. However, this might change if we use a factor as coefficient of the x-varible, but in this case we don't have that.
Therefore, the period of both trigonometric functions is
.
Now, the images of each function is the y-variable set values that defines each function.
So, the function
has an image defined by the set
. It's impotant to notice that the range of a standard function is [-1,1], however, in this case, the function was shifted 1 unit up and it was streched by a factor of 4, that's why the standard image changes to
.
About the second function
, the image set is
, because the function was streched by a factor of 2.
Additionally, the image attached shows the graph of the given functions.
<h3>
Answer: D. 3</h3>
This is a 30-60-90 triangle. The shortest leg (opposite the smallest angle) is half that of the hypotenuse, so y = 6/2 = 3.
Extra info: The long leg is sqrt(3) times the short leg, so x = y*sqrt(3) = x = 3*sqrt(3)
What is 60/50 as a percentage?
it would be 120
When it's x²/a² - y²/b²=1 it's the one with zeros on the x axis, at x=±a, y=0.
Here the zeros are at (±5,0) so that's the first page, second graph.
Answer:
Step-by-step explanation:
Probability = 4/46 = 2/23
(2/23) *100 = 200/23 = 8.69% = 8.7%