Answer step-by-step explanation:
We know that the critical t value for a 98% confidence level for a sample of size n = 18:
Finding degrees of freedom (n-1) = 17
-search the information in table t for 0.98 and find that t = 2.567
As you can see below, in
red is <span>g(x) = (x + 1)^3 and in
blue is f(x)=x^3. Adding 1 to x
moves the graph to the left by 1. Hope this was the answer you were looking for and I hope you have a great day!
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Answer:
0.2 or 20%
Step-by-step explanation:
If the times of arrival vary uniformly, there is an equal chance of an employee reporting at any given time between 8:40 and 9:30.
The range between 8:40 and 9:30 is 50 minutes.
The range between 9:00 and 9:10 is 10 minutes.
Therefore, the probability that a randomly chosen employee reports to work between 9:00 and 9:10 is:

The probability is 0.2 or 20%.