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3 years ago

The place value of the 3 in 27.4359 is _____.

Mathematics

2 answers:

melisa1 [442]3 years ago

8 0

In the hundreds place so its 300

Mademuasel [1]3 years ago

6 0

The place value for 3 in 27.4359 is hundredth.
Hope this helps :3

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The radius of a cylinder is 5" and the lateral area is 70 pi sq. In. Find the length in altitude

aev [14]

We are to solve for the value of the altitude of the given cylinder which has a radius of 5 feet and a lateral area of 70pi ft². To solve this we should recall that the formula in solving the lateral area of a cylinder is Lateral Area = 2pi*r*h. The solution is shown below:
r is equal to 5 ft
lateral area = 70pi
Solving for h, we have:
70pi = 2pi*5*h
70pi / 2pi = 5h
35 = 5h
divide both sides by 5, we have:
35/5 = 5h/5
7 = h

The answer for the length of the altitude is 7 feet.

8 0

2 years ago

Triclosan is a compound often added to products such as soaps, lotions, and toothpaste. It is antimicrobial, so for that reason,

miv72 [106K]

Answer:

The appropriate alternative hypothesis is, Hₐ: p₁ - p₂ > 0.

Step-by-step explanation:

In this case it is provided that Triclosan is a compound often added to products such as soaps, lotions, and toothpaste.

Since the compound is antimicrobial its corporate producer maintained that it should help prevent staph infections among people who use products containing the compound.

But a scientist wants to test whether the compound actually is associated with higher incidence of staph infection.

That is he wants to determine whether people with a detectable level of triclosan have higher rates of carrying the staph bacteria than people without triclosan.

Denote:

Group 1: people with a detectable level of triclosan

Group 2: people without a detectable level of triclosan

To test this the hypothesis can be defined as follows:

H₀: The proportion of people with a detectable level of triclosan does not have higher rates of carrying the staph bacteria than people without triclosan, i.e. p₁ - p₂ ≤ 0.

Hₐ: The proportion of people with a detectable level of triclosan have higher rates of carrying the staph bacteria than people without triclosan, i.e. p₁ - p₂ > 0.

Thus, the appropriate alternative hypothesis is, Hₐ: p₁ - p₂ > 0.

6 0

3 years ago

GCF of 9ab^2 and 6bc^2

Alchen [17]

For this case we have that by definition, the GCF (Greatest Common Factor) is the largest integer that divides the numbers.

We have the following expressions:

$9ab ^ 2\\6bc ^ 2$

We find the factors of 9 and 6:

$9: 1,3,9\\6: 1,2,3,6$

Thus, the largest number that divides 9 and 6 is 3

It is also observed that "b" is the common variable of both expressions

Therefore, the GCF of the expressions is:

$3b$

Answer:

$3b$

8 0

3 years ago

You open a bank account with $100 and deposit 15 every week. Create an equation to model the total amount of money,y, in dollars

Charra [1.4K]

Answer:

$Y = 15x+ 100$

x = 10 months

Step-by-step explanation:

Given:

Initial deposit = $100

Weakly deposit = $15

Solution:

We need to create an equation where total amount is y is equal to initial deposit plus multiplication of weakly deposit and month x, so the equation is written as.

$Y = 15x+ 100$ ---------(1)

Where:

Y = Total amount

x = Number of months.

Second thing we need to find the month for y = $250

Now, we substitute y = 250 in equation 1.

$250 = 15x+ 100$

$15x=250-100$

$15x =150$

$x=\frac{150}{15}$

x = 10 months

Therefore, we need to required 10 months for $250.

4 0

3 years ago

No links or wrong answers please!! 55 points

juin [17]

The areas of the figures are 4(x + 1), 7(d + 4) and y(y + 3)

<h3>How to determine the total areas?</h3>

The figure 1

In this figure, we have

Length = x + 1

Width = 4

The area is calculated as:

Area = Length * Width

So, we have

Area = 4(x + 1)

The figure 2

In this figure, we have

Length = d + 4

Width = 7

The area is calculated as:

Area = Length * Width

So, we have

Area = 7(d + 4)

The figure 3

In this figure, we have

Length = y + 3

Width = y

The area is calculated as:

Area = Length * Width

So, we have

Area = y(y + 3)

Hence, the areas of the figures are 4(x + 1), 7(d + 4) and y(y + 3)