Answer:
x= 7.87298334621 x=.12701665379
Step-by-step explanation:
This is in standard form so we have to factor this into
x^2-8x + 16 + 1 = 16
(x-4)^2 = 15
(x-4) = 
x-4= ± 3.87298334621
x-4 = 3.87298334621 x-4= -3.87298334621
x= 7.87298334621 x=.12701665379
Your're lucky am going to help. Kidding. :D
All real numbers but 3 and -3
Set x as adult tickets.
Set y as children's tickets.
x + y = 15
30x + 20y = 270
Solve for x in the first equation.
x + y = 15
x = 15 - y
Plug this into the second equation.
30x + 20y = 270
30(15 - y) + 20y = 270
450 - 30y + 20y = 270
450 - 10y = 270
-10y = -180
y = 18
If there is 18 childrens tickets, there should be -3 adult tickets.
This is impossible, and this impossible answer occured because the question is written wrong.
There are a total of 15 tickets
The smallest costing ticket is the childrens ticket, which costs 20$.
If he only bought children tickets, this would be 20x15 which is 300$.
300$ is over 270$, which makes the question impossible.
Answer:5/28
Step-by-step explanation:
Answer:
192
Step-by-step explanation:
To find how many phones are expected to be defective, we need to represent the values in a fraction.
x = number of defective phones
Now we can solve this using algebra.
To get the value of x we need to multiply both sides by 8000 to leave x alone.
So around 192 cell phones are expected to be defective out of 8000 phones.
