The place value of the 3 in 27.4359 is ____

Values for the labor force participation rate of women (LFPR) are published by the U.S. Bureau of Labor Statistics. A researche

Anna [14]

Answer:

(A) For this research we made use of the paired t test.

(B) For the t test, we conclude that in the null Hypothesis H₀, there was no difference between the average labor force participation rate for women between the years of 1968 and 1972 as against the alternate Hypothesis Hₐ.

From the output data we have, since the P value is 0.024 and is lesser than the alpha value of 0.05, we will accept the alternate Hypothesis instead of the null Hypothesis.

Note:Kindly find an attached copy of the complete question below.

Step-by-step explanation:

Solution

Recall that:

The U.S of Bureau of Labor Statistics have published Values for the labor force participation rate of women (LFPR).

We are more interested in if there was a difference between female participation 1968 and 1972, a rapid change in women.

so we will check values for 19 randomly selected cities for 1968 and 1972,

Now,

(a) Which of this test is most appropriate for this data

The test which will be more suitable for these data will be paired to test t.

Because the data is for labor force participation for two different years, we apply the t test. now that we are making a comparison of two different year times, we will apply the t test in this research.

In this case, the sample size for both the years evaluated should be same, since we need to pair each and all the data.

(b)By using the test you selected, explain your conclusion

Now, to test the data paired t test, we have already the null Hypothesis H₀: In this case there is no difference between the average labor force participation rate for women between the years of 1968 and 1972 as compared with the alternate Hypothesis Hₐ: there was a significant difference between the average labor force participation rate for women between the years of 1968 and 1972.

However, from the output, we have that the P value is 0.024 which is lower than the alpha value of 0.05.

In conclusion, the alternate Hypothesis accepted while the null Hypothesis is rejected.

Note: kindly find an attached copy of the complete question to this solution

below.

4 0

3 years ago

Identify an equation in slope intercept form for the LINE parrelel to y=5x+2 that passes through - 6,-1

nlexa [21]

Answer:

y = 5x-1

Step-by-step explanation:

parallel lines have the same slope.

y intercept: -1

slope: 5

- 1 is the same as +-1

so, y = 5x-1

7 0

3 years ago

Three listening stations located at (3300, 0), (3300, 1100), and (-3300, 0) monitor an explosion. The last two stations detect t

erastovalidia [21]

Answer:

The coordinates of the explosion is (3300, -2750)

Step-by-step explanation:

I have plot the points and attached to thus answer for easy understanding.

Now, from the question, since station A is the first to hear the explosion, we'll make it the foci of the parabola in the graph I attached and it will be horizontal since the distance between station C and A is much more than that between station B and A. Thus, the reason why station C will have to be the other foci with the hyperbola centred at the origin.

Now, sound travels at a speed of 1100 ft/s and station B is located 1100 ft from station A. Thus, the explosion would likely have occurred at a point on the line x = 3300ft . Since station A is 3300ft from centre C = 3300,hence C² = 3300² = 10,890,000. Since it takes 4 seconds longer for the sound to reach station C than A, the sound has traveled 4(1100)= 4400 ft.

Thus, 4400 = d1 = d2 = 2a

So,2a = 4400 and so, a =2200

a² = 2200² = 4,840,000 where d1 is the distance from station C to the explosion and d2 is the distance from station A to the explosion. To find b², let's use the equation ;

c² = a² + b² and so; b² = c² - a² = 10,890,000 - 4,840,000 = 6,050,000

Equation of hyperbola is given as;

(x²/a²) - (y²/b²) = 1

Plugging in the values of a² and b², we obtain ;

(x²/4,840,000) - (y²/6,050,000) = 1

Since we have deduced that the explosion must occur on the line x= 3300, we'll put in 3300 for x to obtain ;

(3300²/4,840,000) - (y²/6,050,000) = 1

2.25 - 1 = (y²/6,050,000)

y² = (1.25 x 6,050,000)

y² = 7562500

y = √7562500

y = ± 2750

Due to the fact that the explosion will occur at a point further from station B than from station A, the explosion will take place in quadrant 4. Thus, we will take the negative value of y which is - 2750.

So explosion will occur at the coordinate (3300, -2750)