Answer:
y'(t)=ky(t)(100-y(t))
Step-by-step explanation:
The rate of change of y(t) at any time is the derivative of y with respect to time y, y'(t)
If y(t) is the percent of the population advocating war at time t
then 100-y(t) is the percent of the population not advocating war
The product of the percentage of the population advocating war and the percentage not advocating war would be
y(t)(100-y(t))
If the rate of change of y(t) at any time is proportional to the product of the percentage of the population advocating war and the percentage not advocating war, then
y'(t)=ky(t)(100-y(t))
where <em>k is the constant of proportionality
</em>
Answer:
105°
Step-by-step explanation:
180 minus 75 from angle 6 would give you angle 3.
She’s in love with the boy and Check yes or No
Answer:
0.0668 = 6.68% probability that the worker earns more than $8.00
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
The average hourly wage of workers at a fast food restaurant is $7.25/hr with a standard deviation of $0.50.
This means that 
If a worker at this fast food restaurant is selected at random, what is the probability that the worker earns more than $8.00?
This is 1 subtracted by the pvalue of Z when X = 8. So



has a pvalue of 0.9332
1 - 0.9332 = 0.0668
0.0668 = 6.68% probability that the worker earns more than $8.00
Answer:
Simplify−412+16t+48.h=16t−1633
Step-by-step explanation: