16 minutes
0.03*16=0.48
Closest you can get w/out going over.
Answer:
24/9
Step-by-step explanation:
The first one is not proportional and the second one is proportional
Given : The Area of the Rectangle = x⁴ - 100
We know that : (a + b)(a - b) = a² - b²
⇒ x⁴ - 100 can be written as : (x²)² - (10)²
⇒ (x²)² - (10)² can be written as : (x² + 10)(x² - 10)
We know that, Area of a Rectangle is given by : Length × Width
Comparing (x² + 10)(x² - 10) with Area of the Rectangle formula, We can notice that :
⊕ Length = x² + 10
⊕ Width = x² - 10
Given : Length of the Rectangle is 20 units more than Width
⇒ Width + 20 = Length
⇒ x² - 10 + 20 = x² + 10
⇒ x² + 10 = x² + 10
<u>Answer </u>: x² - 10 represents the width of the rectangle. Because the area expression can be rewritten as (x² - 10)(x² + 10) which equals
(x² - 10)((x² - 10) + 20)
⇒ Option A
Answer:
The first mechanic $90/hour and the second charged $70/hour
Step-by-step explanation:
Lets start off by letting x be the first mechanics rate and y being the second mechanics rate. We know that the first mechanic worked 5 hours and that the second mechanic worked 10 hours and together they charged 1150. An equation to express this would be:
5x+10y = 1150
We also know that together they charged 160/per hour. An equation to express this would be:
x+y = 160
Now we can solve the second equation for x or the first mechanics rate.
x+y = 160
x = 160 - y
Now that we have an expression for x we can plug that back into the first equation and solve for y or how much the second mechanic charged.
5x+10y=1150 plug in x =160-y
5(160-y)+10y=1150 Distribute
800 -5y+10y = 1150 Combine like terms
800 +5y = 1150 Subtract 800 from both sides
5y = 350 divide by 5
y = 70
So we know that the second mechanic charged $70/hour. We also know that(from our work before) that the first mechanic charges $160 - the rate the second mechanic charged. We know that's $70/hour so we can plug in and solve for the first rate.
x = 160-y
x = 160-70
x = 90
So we know that the first mechanic charged $90/hour and the second mechanic charged $70/hour.
