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Misha Larkins [42]

3 years ago

14

1) The membership fee of Math Club is P25. What is the total amount

1 answer:

AURORKA [14]3 years ago

5 0

Answer:

it's actually none of those the answer I have is p 31,300

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Simplify <img src="https://tex.z-dn.net/?f=%28r%5Cfrac%7B1%7D%7B2%7D4" id="TexFormula1" title="(r\frac{1}{2}4" alt="(r\frac{1}{2

Katena32 [7]

Hello!!

════ ⋆★⋆ ════

$\mathbb{A~N~S~W~E~R~:}$

$= r$ · $2$

➡ $\Huge \sf \mathbb \color{}\underline{\colorbox{ANSWER~WITH~EXPLANATION ~!}{}}$

$\mathfrak{apply~the~fraction~rule: }$ $a$ $\frac{b}{c} =\frac{a~. ~b }{c}$

$\mathfrak{apply~rule: }$ $a$ · $1 = a$

$r$ · $1$ · $4 = r$ · $4$

$=\frac{r~.~4}{2}$

$\mathfrak{divide~the~numbers~: }$ $\frac{4}{2} = 2$

$= r$ · $2$

So, your answer will be is :

$= r$ · $2$

$\color{}{Hope\:it\:helps. ..}$

#LearnWithBrainly

$\mathbb{A~N~S~W~E~R~:}$

$\mathfrak{Jace}$

4 0

3 years ago

What's the scientific notation of 0.000028

Dmitry_Shevchenko [17]

2.8 x 10^-5 good luck

7 0

4 years ago

Read 2 more answers

Test the series for convergence or divergence (using ratio test)

Triss [41]

Answer:

$\lim_{n \to \infty} U_n =0$

Given series is convergence by using Leibnitz's rule

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given series is an alternating series

∑ $(-1)^{n} \frac{n^{2} }{n^{3}+3 }$

Let $U_{n} = (-1)^{n} \frac{n^{2} }{n^{3}+3 }$

By using Leibnitz's rule

$U_{n} - U_{n-1} = \frac{n^{2} }{n^{3} +3} - \frac{(n-1)^{2} }{(n-1)^{3}+3 }$

$U_{n} - U_{n-1} = \frac{n^{2}(n-1)^{3} +3)-(n-1)^{2} (n^{3} +3) }{(n^{3} +3)(n-1)^{3} +3)}$

Uₙ-Uₙ₋₁ <0

<u><em>Step(ii):-</em></u>

$\lim_{n \to \infty} U_n = \lim_{n \to \infty}\frac{n^{2} }{n^{3}+3 }$

$= \lim_{n \to \infty}\frac{n^{2} }{n^{3}(1+\frac{3}{n^{3} } ) }$

= $= \lim_{n \to \infty}\frac{1 }{n(1+\frac{3}{n^{3} } ) }$

$=\frac{1}{infinite }$

=0

$\lim_{n \to \infty} U_n =0$

∴ Given series is converges

3 0

3 years ago

What value of r is the solution of the equation 3/4r = 7/3

Liula [17]

R= 28/9. Hope this helps

4 0

3 years ago

Find two consecutive integers whose sum is 73. Which of the following equations could be used to solve the problem?

max2010maxim [7]

2x + 1 = 73

2x = 72
x = 36

the 2 integers are 36 and 37

Its b

8 0

4 years ago

Read 2 more answers