Answer:
A pheochromocytoma is a tumor in the adrenal gland. It causes the gland to make too much of the hormones epinephrine and norepinephrine.
Explanation:
<span>In Drosophila + indicates wild-type allele for any gene, m is mahogany and e is ebony.
Female parents are m+/m+ and males are +e/+e.
F1 are m+/+e, all wild type. F1 females are crossed with me/me males - the test cross.
Offspring will be : non recombinant m+/me, mahogany wild type or +e/me wild type ebony. OR
recombinant me/me mahogany ebony or ++/++ wild type.
As the two genes are 25 map units apart, the percentage of recombinants will be 25% and therefore percentage parental types will be 75%.
75% 1000 is 750. There are two parental types, so you would expect 375 of each. Therefore, you would expect 375 m+/me and 375 +e/me.
25% of 1000 is 250 split between two recombinants =125 of each. Therefore you would expect 135 me/me and 125 ++/++</span>
Answer:
I would expect to see a greater variety of traits observed. Simplistically, I would expect to see people with blue eyes and brown hair, blonde hair or red hair. Whereas in a population where chromosomes do not cross over, I would expect to see traits that are more frequently associated with each other. For example, I would expect to see a greater proportion of blue eyed people to be blonde because the gene for hair colour is more frequently associated with the gene for eye colour.
Explanation:
Answer:
B
the trna will not be recognized by trna synthetase and cannot be charged
