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Art [367]
3 years ago
12

Write a method called all Less that accepts two arrays of integers and returns true if each element in the first array is less t

han the element at the same index in the second array. For example, if the two arrays passed are {45, 20, 300} and {50, 41, 600}, your method should return true. If the arrays are not the same length, you should return false.Test your method and print out to the screen in main() function the following callsa. all Less(arr1, arr2); (where arr1 = [1,2,3,4,5], arr2 = [4,5,6,7,8])b. all Less(arr1, arr2); (where arr1 = [1,2,3,4,5], arr2 = [5,6,7,8])c. all Less(arr1, arr2); (where arr1 = [5,2,3,4,1], arr2 = [4,5,6,7,8])d. all Less(arr1, arr2); (where arr1 = [5,5,3,4,5], arr2 = [9,9,9,9,1])
Computers and Technology
1 answer:
GaryK [48]3 years ago
8 0

Answer:

The program to this question can be given as:

Program:

#include<iostream> //header file

using namespace std; //using name space

bool allLess (int arr1[], int arr2[]) //defining method allLess  

{

int a,b; //define variable

a=  *(&arr1 + 1) - arr1; //hold length of arr1

b=  *(&arr2 + 1) - arr2; //hold length of arr2

if(a!=b) //checking condition  

{

return 1; //return value

}

for(int i=0; i<a; i++) //loop

{

if( arr1[i]>=arr2[i]) //checking condition

{

return 1; //return value

}

}

return 0; //return value

}

int main() //define main method.

{

   int arr1[]={1,2,3,4,5}; //define array arr1 and assign value.

   int arr2[]={4,5,6,7,8}; //define array arr2 and assign value.

   cout<< allLess(arr1,arr2); //function calling

   return 0;

}

Output:

1

Explanation:

The Explanation of the C++ language program can be given as follows:

  • In the above program firstly we include the header file. Then a method is defined that is "allLess" this method accepts two arrays that are "arr1 and arr2". This function returns a boolean value that is true or false.
  • Inside a function, we define a conditional statement and a loop in the if block we check the length of the arr1 array variable is not equal to arr2 array length. if this condition is true it will return false.
  • In the loop, we define another if block in this block we check that if arr1 array elements are grater then equal to arr2 array element if this condition is true it will return false. At the end of both if block and loop the function will return a value that is "true".
  • In the main method, we define two arrays and pass to the function and use (cout function) for print return value.
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The procedure call mystery(38) will yield which output? __________ a) 0 12 b) 12 0 c) 1 1 0 2 d) 1 1 1 1 e) 2 0 1 1 public void
Ivan

Answer:

Option b is the correct answer for the above question.

Explanation:

  • The mystery function is a recursive function that calls for the two times when the user passes 38 on the argument.
  • The first value is 38 and the second value is 2 for which that function is called.
  • When the value 38 is passed, then again 2 is passed because of the "mystery (n % 3);" statement.
  • This statement holds by the if condition which gives the true when the argument value is greater than 2.
  • Hence for the 2 value the if condition will not true and the function is not called again.
  • Then the 38/3 and 2/3 are printed whose value is 12 0, but it will print 0 12 because of the recursive function.
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Answer:

   public static int[] listLengthOfAllWords(String [] wordArray){

       int[] intArray = new int[wordArray.length];

       for (int i=0; i<intArray.length; i++){

           int lenOfWord = wordArray[i].length();

           intArray[i]=lenOfWord;

       }

       return intArray;

   }

Explanation:

  1. Declare the method to return an array of ints and accept an array of string as a parameter
  2. within the method declare an array of integers with same length as the string array received as a parameter.
  3. Iterate using for loop over the array of string and extract the length of each word using this statement  int lenOfWord = wordArray[i].length();
  4. Assign the length of each word in the String array to the new Integer array with this statement intArray[i]=lenOfWord;
  5. Return the Integer Array

A Complete Java program with a call to the method is given below

<em>import java.util.Arrays;</em>

<em>import java.util.Scanner;</em>

<em>public class ANot {</em>

<em>    public static void main(String[] args) {</em>

<em>       String []wordArray = {"John", "James", "David", "Peter", "Davidson"};</em>

<em>        System.out.println(Arrays.toString(listLengthOfAllWords(wordArray)));</em>

<em>        }</em>

<em>    public static int[] listLengthOfAllWords(String [] wordArray){</em>

<em>        int[] intArray = new int[wordArray.length];</em>

<em>        for (int i=0; i<wordArray.length; i++){</em>

<em>            int lenOfWord = wordArray[i].length();</em>

<em>            intArray[i]=lenOfWord;</em>

<em>        }</em>

<em>        return intArray;</em>

<em>    }</em>

<em>}</em>

This program gives the following array as output: [4, 5, 5, 5, 8]

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