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viktelen [127]
3 years ago
15

Please anyone, help me.... I'm not sure how to put these all together. 35 points!

Computers and Technology
2 answers:
Zolol [24]3 years ago
8 0

Answer: I can confirm DoggyMan5 is correct.

Vilka [71]3 years ago
7 0

Answer:

#School Name

school_name = "Klein Cain"

# Asks for name

full_name = input("Please enter your full name ")

#Says Hello

print("Hello, ", full_name, "!!")

#Says the letters in your name

print("There is ", len(full_name), " letters in your name")

#Says final message

print("??? is a Cain where??? ", school_name)

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pishuonlain [190]

Answer:

print preview

Explanation: platooo

8 0
3 years ago
Why did the boy run from the pillow...... wrong answers only
Savatey [412]

He thinks there is a demon hiding innit thus, he runs and calls his mom. His mom says "Jimmy there's nothing in that pilow young man!" Jimmy walks back to his room scared if its still there. He hops into bed hoping that he can get a good nights rest. The next day, Jimmy asks if he can go buy another pillow. His mom says "As long as it makes you feel safe then ok." Young Jimmy, jumping in excitement, goes to the checkout zone to buy his new pillow. When they get home, Jimmy and his mom eat dinner and then head for bed. Jimmy hops into bed and knows that everything will be ok. The end.

4 0
3 years ago
Add (total) all the number in the list (below) using a for loop, but skip over the number at index 3.
user100 [1]

Answer:

The program in Python is as follows:

numbers = [10,20,30,40,50,60,100]

total = 0

for i in range(len(numbers)):

   if i != 3:

       total+=numbers[i]

print(total)

Explanation:

This initializes the list

numbers = [10,20,30,40,50,60,100]

Set total to 0

total = 0

This iterates through numbers

for i in range(len(numbers)):

This ensures that the index 3, are not added

<em>    if i != 3:</em>

<em>        total+=numbers[i]</em>

Print the calculated sum

print(total)

3 0
3 years ago
Write a program that prompts the user to enter a series of numbers between 0 and 10 asintegers. The user will enter all numbers
Anna71 [15]

Answer:

The program in Python is as follows:

import collections

from collections import Counter

from itertools import groupby

import statistics

str_input = input("Enter a series of numbers separated by space: ")

num_input = str_input.split(" ")

numList = []

for num in num_input:

         if(num.lstrip('-').isdigit()):

                   if num[0] == "-" or int(num)>10:

                             print(num," is out of bound - rejecting")

                   else:

                             print(num," is valid - accepting")

                             numList.append(int(num))

         else:

                   print(num," is not a number")

print("Largest number: ",max(numList))

print("Smallest number: ",min(numList))

print("Range: ",(max(numList) - min(numList)))

print("Mode: ",end = " ")

freqs = groupby(Counter(numList).most_common(), lambda x:x[1])

print([val for val,count in next(freqs)[1]])

count_freq = {}

count_freq = collections.Counter(numList)

for item in count_freq:

         print(item, end = " ")

         lent= int(count_freq[item])

         for i in range(lent):

                   print("#",end=" ")

print()

Explanation:

See attachment for program source file where comments are used as explanation. (Lines that begin with # are comments)

The frequency polygon is printed using #'s to represent the frequency of each list element

7 0
2 years ago
A department manager would like to choose an access control model in which the owner of a resource decides who may modify permis
Hoochie [10]

Answer: Discretionary access control (DAC)

Explanation: Discretionary access control is the control system that is imposed over the information system. The information systems contains different objects and subjects that gets the permission to do the operations.

The operation which the components can do are sharing the data to other object or subjects, privilege providence, change in the rules for the access, security entities getting changed etc.

4 0
3 years ago
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