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Mandarinka [93]
4 years ago
8

As a part-time contractor, you want to test a new cement mixture for a project. You need 2 34 wheelbarrows of sand to make 8 whe

elbarrows of concrete. How much sand will you need to make 248 cubic feet of concrete?
Mathematics
2 answers:
romanna [79]4 years ago
7 0

Answer: He would need 10.07 cubic feet of sand for wheelbarrows.

Step-by-step explanation:

Since we have given that

Ratio of wheelbarrows of sand to wheelbarrows of concrete is given by

2\dfrac{3}{4}:8\\\\=\dfrac{11}{4}:8\\\\=11:32

Volume of concrete for wheelbarrows = 248 cubic feet.

Then volume of wheelbarrows of sand would be

(\dfrac{11}{32})^3=\dfrac{x}{248}\\\\\dfrac{1331\times 248}{32^3}=x\\\\10.07=x

Hence, he would need 10.07 cubic feet of sand for wheelbarrows.

nirvana33 [79]4 years ago
6 0

Answer: 85 1/4 cubic feet

Step-by-step explanation:

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Which table represents a direct variation function? A table with 6 columns and 2 rows. The first row, x, has the entries, negati
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Answer:

The correct option is;

A table with 6 columns and 2 rows. The first row, x, has entries, negative 3, negative 1, 2, 5, 10. The second row, y, has entries, negative 7.5, negative 2.5, 5.0, 12.5, 25

Please find attached the graphs of the table data

Step-by-step explanation:

Each of the given table data of in the tables are analysed to find direct variation;

Table 1

x,               -3,                 -1,                 2,                5,                10

y,              -4.5,              -3.0,             -1.5,             0.0,              1.5              

-4.5/-3  = 1.5 ≠ -3.0/-1 = 3

No direct variation

Table 2      

x,             -5.5,               -4.5,            -3.5,            -2.5,             -1.5

y,              10,                   8,                 6,              4,                  2

10/(-5.5) = -20/11  ≠ 8/(-4.5) = -16/9

However, 10/(-5.5 + 0.5) = -2 = 8/(-4.5 + 0.5) = -2

Adjusted direct variation

Table 3              

x,              -5.5,               -5.5,             -5.5,           -5.5,            -5.5

y,              -3,                    -1,                 2,                5 ,              10                  

-3/(-5.5) ≠ -1/-5.5

No direct variation

Table 4

x,              -3,                    -1,                2,                  5,             10

y,              -7.5,                 -2.5,            5.0 ,              12.5,         25  

 -7.5/-3 = 2.5 = -2.5/(-1) = 5.0/2 = 12.5/5 =25/10

Direct variation exists        

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