Ask question

Ask question

All categories

2 years ago

15

Dana ordered 6 pizzas for her party and each pizza is sliced into quarters. She says in order to find out how many slices there

are, she needs to calculate 6 ÷ 1/4 Which multiplication expression will also solve the problem of how many slices there are?
A.24 x 1/6
B.4 x 1/6
C.6 x 1/4
D.6 x 4
Please Help!!

2 answers:

Rama09 [41]2 years ago

8 0

Answer: C. 6 x 1/4

Step-by-step explanation:

hope it helps!

olya-2409 [2.1K]2 years ago

7 0

Answer:

D 6x4

Step-by-step explanation:

so i had this in a test and this was the correct answer, so i wanna help others.

its D 6x4

You might be interested in

Please help me with this!!!!!!!!!!!!!!! MATHHHHHH

Alexeev081 [22]

I can’t see anything on the screen

4 0

2 years ago

1/2(n-5)=1/2(23-5) I cannot find what’s half of 23-5

liraira [26]

Answer:

n = 23

Step-by-step explanation:

if 1/2 (n-5) = 1/2 (23-5)

that must mean that n=23.

and if you are just looking for 1/2 of 23-5 that is just 9. (23-5) = 18 and half of 18 is 9

3 0

3 years ago

Suppose approximately 75% of all marketing personnel are extroverts, whereas about 70% of all computer programmers are introvert

Setler [38]

Answer:

$P(x \ge 5) = 1.000$ ---- At least 5 from marketing departments are extroverts

$P(x=15) = 0.013$ ---- All from marketing departments are extroverts

$P(x = 0) = 0.002$ ---------- None from computer programmers are introverts

Step-by-step explanation:

See comment for complete question

The question is an illustration of binomial probability where

$P(x) = ^nC_x * p^x * (1 - p)^{n-x}$

$(a):\ P(x \ge 5)$

$n = 15$ --- marketing personnel

$p = 75\%$ --- proportion that are extroverts

Using the complement rule, we have:

$P(x \ge 5) = 1 - P(x < 5)$

So, we have:

$P(x < 5) =P(x = 0) + P(x = 1) + P(x = 2) + P(x = 3) + P(x = 4)$

$P(x = 0) = ^{15}C_{0} * (75\%)^0 * (1 - 75\%)^{15 - 0} = 1 * 1 * (0.25)^{15} = 9.31 * 10^{-10}$

$P(x = 1) = ^{15}C_{1} * (75\%)^1 * (1 - 75\%)^{15 - 1} = 15* (0.75)^1 * (0.25)^{14} = 4.19 * 10^{-8}$

$P(x = 2) = ^{15}C_{2} * (75\%)^2 * (1 - 75\%)^{15 - 2} = 105* (0.75)^2 * (0.25)^{13} = 8.80 * 10^{-7}$

$P(x = 3) = ^{15}C_{3} * (75\%)^3 * (1 - 75\%)^{15 - 3} = 455* (0.75)^2 * (0.25)^{12} = 0.0000153$

$P(x = 4) = ^{15}C_{4} * (75\%)^4 * (1 - 75\%)^{15 - 4} = 1365 * (0.75)^4 * (0.25)^{11} = 0.000103$

So, we have:

$P(x < 5) = (9.31 * 10^{-10}) + (4.19 * 10^{-8}) + (8.80 * 10^{-7}) + 0.0000153 + 0.000103$

$P(x < 5) = 0.00011922283$

Recall that:

$P(x \ge 5) = 1 - P(x < 5)$

$P(x \ge 5) = 1 - 0.00011922283$

$P(x \ge 5) = 0.9998$

$P(x \ge 5) = 1.000$ --- approximated

$(b)\ P(x = 15)$

$n = 15$ --- marketing personnel

$p = 75\%$ --- proportion that are extroverts

So, we have:

$P(x) = ^nC_x * p^x * (1 - p)^{n-x}$

$P(x=15) = ^{15}C_{15} * 0.75^{15} * (1 - 0.75)^{15-15}$

$P(x=15) = 1 * 0.75^{15} * (0.25)^{0$

$P(x=15) = 0.013$

$(c)\ P(x = 0)$

$n=5$ ---------- computer programmers

$p = 70\%$ --- proportion that are introverts

So, we have:

$P(x) = ^nC_x * p^x * (1 - p)^{n-x}$

$P(x = 0) = ^{5}C_0 * (70\%)^0 * (1 - 70\%)^{5-0}$

$P(x = 0) = 1 * 1 * (0.30)^5$

$P(x = 0) = 0.002$

3 0

2 years ago

2.) If z varies inversely as r, and z= 24 when r = 6, find r when z= 12

Schach [20]

Step-by-step explanation:

........ .......... ....

7 0

2 years ago

Determine which postulate or theorem can be used to prove that ABC=DCB

lianna [129]

Answer with explanation:

In Δ ABC and ΔD BC

∠A=∠D-------Given

∠ABC=∠DCB-------Each being 90° given in the Diagram.

Side, BC is Common.

⇒⇒Δ ABC ≅ ΔD BC-------[AAS]

When two triangles are congruent , their areas are equal.

So, Area(ABC)=Area (DCB)

Option B :⇒ A AS

3 0

3 years ago

Read 2 more answers