Answer:
<h2>There are infinite possible values for a and b there.</h2>
Step-by-step explanation:
.
In the above equation the proper values can not be found only when the denominator will be 0.
As for example, if a = 2, then b = 0.12.
If a = 0.12, then b = 2.
If a = 1, b = 0.24 or b = 1, a = 0.24.
Thus, a or b can be any real number rather than 0.
Let's check the first polynomial , that is
We need to factor it first and for that we have to do grouping and factoring .
TO find the roots, we need to set P(x) to 0, that is
SO the correct option is A .
The answer is -4, -4. I hope this helped
The answer is valid for number 4
Hello,
Let's r the ration
We suppose x ≠0
x=r*(x-2)==>r=x/(x-2)
x+3=r*x==> (x+3)/x=x/(x-2)==>(x+3)(x-2)=x²
==>x²+3x-2x-6=x² ==>x-6=0==>x=6
x-2=6-4=4
x=6
x+3=6+3=9
6=4*3/2
9=6*3/2
Ration 3/2
First term: 4