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2 years ago

Tell whether each of the following is a function.

1 answer:

n200080 [17]2 years ago

6 0

Options A, C and D are functions.

In a function, for every number for 'x' there is only one 'y'. So, if you have two ordered pairs in a choice that have the same number for 'x', that is not a function.

Remember an ordered pair is written (x, y).

B is not a function as:
(x, y)
(1, -2)
(1, -3)
(1, -4)
^ All of the x-coordinates are the same.

E is not a function as:
(x, y)
(6, -1)
(6, -8)
^ Two of the x-coordinates are the same.

Thus, A, C and D are functions.

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At the soup to nuts cafeteria, larry orders two pieces of toast and a bagel, which comes out to $\$1.30$. Curly orders a bagel a

kotegsom [21]

Let us take costs of a piece of toast = $t, , one bagel cost=$b and a muffin cost=$m.

Larry

Two pieces of toast and a bagel cost = $1.30

2t+b=1.30 -------------equation(1)

Let us solve the equation(1) for t in terms of b, because we need to find one bagel cost.

Subtracting b from both sides we get

2t+b-b=1.30-b

2t= 1.30-b

Dividing by 2 on both sides.

2t/2= (1.30-b)/2

t= (1.30-b)/2

Curly

A bagel and a muffin cost = $2.50.

b + m = 2.50 -------------equation(2)

Solving equation for m in terms of b, we get

m= 2.50-b.

Moe

A piece of toast, two bagels, and three muffins cost = $6.95

t + 2b + 3m = 6.95 ......................equation(3).

Substituting t= (1.30-b)/2 and m= 2.50-b in equation (3)

(1.30-b)/2 + 2b + 3(2.50-b) = 6.95 .

Multiplying each term by 2 to get rid 2 from denominator of (1.30-b).

2*(1.30-b)/2 + 2*2b + 2*3(2.50-b) = 2*6.95

1.30-b + 4b + 6(2.50-b) = 13.90.

1.30 - b + 4b +15 - 6b = 13.90

Combining like terms

-3b +16.30 = 13.90

Subtracting 16.30 from both sides.

-3b +16.30-16.30 = 13.90-16.30.

-3b= -2.4

Dividing both sides by -3.

-3b/-3 = -2.4/-3

b = 0.8

Therefore, cost of one bagel = $0.80.

7 0

3 years ago

What is the answer to <br> 7/9 - 3/8=

antiseptic1488 [7]

7/9-3/8
56/72-27/72
29/72

5 0

3 years ago

A club consisting of 6 juniors and 8 seniors is to be formed from a group of 13 juniors and 16 seniors. How many different clubs

Vilka [71]

Answer: 22,084,920 different clubs

Step-by-step explanation:

The club must have 6 juniors and 8 seniors

We have a total of 13 juniors and 16 seniors.

Now, we know that the possible combinations of N objects into a group of K is equal to:

$C = \frac{N!}{(N-K)!*K!}$

For the juniors we have N = 13 and K = 6

$Cj = \frac{13!}{7!*6!} = \frac{13*12*11*10*9*8}{6*5*4*3*2*1} = 1716$

For the seniors we have N = 16 and K = 8

$Cs = \frac{16!}{8!8!} = \frac{16*15*14*13*12*11*10*9}{8*7*6*5*4*3*2*1} = 12870$

Now, as the group consist on both combinations togheter, the number of different clubs that can be formed are:

C = Cj*Cs = 1,716*12,870 = 22,084,920

5 0

3 years ago

What is 986 divided by 68

Andreyy89

Answer: 14.5

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Help l rely need it plz plz

tangare [24]

I think number 6. Is 45°

6 0

2 years ago