When would you want to use the median over the mean for describing the measure of center for a data set?

1 answer:

8 0

Hello!

Sometimes when there are outliers in a data set, for example 1, 20,25,26,30, one is the outlier and when you find the mean it will not represent the data in the most accurate way. This is when you use the median to represent the part of the data set that has the information that is close together.

I hope this helps!

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Select all the rates equivalent to the rate 3/4 cup per pound

Artemon [7]

Answer:

Step-by-step explanation:

Multiply the decimal by 100 and write the result with the percentage sign: 0.75 × 100 = 75%.

3 0

2 years ago

How many 5-letter words can be made using exactly 5 of the letters from

kow [346]

The total number of ways by words are formed is 35 ways.

According to the statement

We have given that the 5 letters and we have to make word from them and the letters are repeated as equal to letters in given words.

And we have to find the possible ways.

So, The given words are:

TEXAS and MEXICO

Here X = 2 and E = 2 and all other words are one time used words.

We can find possible ways by use of combination and permutation.

So,

Total number of ways = $3C_{1} ^{5} + 2C_{2} ^{5}$

here 3 because three letters are not repeatable and 2 letters are repeated for 2 times.

So,

Total number of ways = $3C_{1} ^{5} + 2C_{2} ^{5}$

Total number of ways = $3(\frac{5!}{1!} ) + 2(\frac{5!}{2!*3!} )$

Total number of ways = $3(5) + 2(10)$

Total number of ways = 15 + 20

Total number of ways = 35.

So, The total number of ways by letters are formed is 35 ways.

Learn more about combination and permutation here

brainly.com/question/11732255

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3 0

1 year ago

The office of student services at a large western state university maintains information on the study habits of its full-time st

solong [7]

A suitable probability calculator can tell you the probability is about 6.7%.

_____

The standard deviation of the distribution of sample means is the population standard deviation (6) divided by the square root of the sample size (√144=12). Thus, your threshold is about (19.25-20)/(6/12) = -1.5 standard deviations from the mean.