Answer:
The answer to your question is
sin Ф = 0.731 and sinФ = -0.731; cos Ф 0.682 and cos Ф = -0.682
Step-by-step explanation:
tan Ф = 1.072, 0 < Ф < 2 π, tan Ф is positive, find the solution in the first and third quadrangle.
- tan Ф = opposite side / adjacent side
- 1.072 / 1 = opposite side / adjacent side
- opposite side = 1.072 and adjacent side = 1
Calculate hypotenuse
c² = a² + b²
c² = 1.072² + 1²
c² = 2.149
hypotenuse = c = 1.466
First quadrangle
sin Ф = 1.072 / 1.466 = 0.731
cos Ф = 1 / 1.466 = 0.682
Third quadrangle
sin Ф = -1.072 / 1.466 = -0.731
cos Ф = -1 / 1.466 = -0.682
Answer:
A≈32
ft²
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To find the surface area of a right rectangular prism you must use this formula A=2(wl+hl+hw)
Then plug in your variebles
A=2( 1.33*1.5+5+1.5+5+1.33)
This comes out to be A≈32 
Answer:
36.25 is equal to the 45.5% of 79.67
Step-by-step explanation:
To solve this you just have to find the value that represents the 100%.
To do this, you can use the Rule of Three that allows you to solve problems of proportions.
In this case, you know that the 45.5% of the magnitude <em>X </em>is 36.25, now you have to find the value which corresponds to the 100%.
Mathematically it will be:

Then you have to solve the equation to find <em>X</em>:

And finally, the answer is:

The difference between the masses is
4.55·10¹³ kg -1.78·10¹² kg
= 4.55·10¹³ kg - 0.178·10¹³ kg
= (4.55 -0.178)·10¹³ kg
= 4.372·10¹³ kg
Rounded to the appropriate precision, the mass of the Antarctic iceberg exceeds that of the Rock of Gibraltar by ...
4.37·10¹³ kg
Answer:
Step-by-step explanation:
We have the polynomial
( 1 )
To solve this problem we have to take into account that only we can sum term with the same order in the variable. We have the polynomials

we can note (by summing term by term) that only the sum of the first and the fourth equation correspond to the given polynomial ( 1 ) of the problem. If we organize these polynomials (that is, write the equation down in a form where higher order appears first ) we have
and if we sum we obtain

that is what we was looking for
I hope this is useful for you
regards