Answer:
part A) rearrange the equations to form simultaneous equations:
y-7x=8
y-5x=-2
now eliminate the y values by minusing the two equations:
(y-7x=8)-(y-5x=-2)
to get:
-2x=-6
x=3
now substitute x into one of the equations to get y:
y=5x-2
y=15-2
y=13
part B) the lines will intercept at (3, 13)
Step-by-step explanation:
hope this helps!
Answer:
30
Step-by-step explanation:
First, we can say that because the men do 1/3 of the work in 20 days,
for 10 men:
20 days = 1/3 total work
Because we need the house built in 30 days, and 20 days have already passed, we only have 30-20=10 days left. Furthermore, 20/2=10, so in our equation of 20 days = 1/3 total work, we can divide both sides by 2 to get
10 days = 1/6 total work
The amount of work we need to get done in 10 days is (all of it) - (1/3 of total work) = 1 - 1/3 = 2/3 = 4/6
Since 10 men can do 1/6 of the work in 10 days, 10*4 =40 men can do 1/6 * 4 = 4/6 of the work in 10 days. This is the amount of work that needs to get done. Therefore, the contractor needs 40 (total workers) - 10 (current workers) = 30 new workers to finish the remaining work in due time
Answer:
non proportional
Step-by-step explanation:
All of the others are correct
C) sqrt(32) = sqrt(2^5)=4sqrt(2), then + sqrt(2) = 5 * sqrt(2)