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Sati [7]
4 years ago
11

What are the amplitude, period, phase shift, and midline of f(x) = −4 cos(3x − π) + 1?

Mathematics
2 answers:
DiKsa [7]4 years ago
6 0

The general function for the cos function is:

<span>y=Acos<span>(B<span>(x+C)</span>)</span></span> where A is the amplitude,  <span><span>2π</span>B</span> is the period and phase shift is C .

For our function: f(x) = −4 cos(3x − π) + 1 =-4cos(3(x-π/3))+1

the amplitude is:-4

the phase shift is: -π/3

Degger [83]4 years ago
6 0

Answer:

Amplitude: 4; period: 2 pi over 3; phase shift: x = pi over 3; midline: y = 1

Step-by-step explanation:

Use the form a cos (bx-c)+d to find the amplitude, period, phase shift, and vertical shift.

a=-4

b=3

c=pi

d=1

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Answer:

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3 0
3 years ago
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Ronch [10]

Answer:

Step-by-step explanation:

Answer:

Data

Equation               25x² + 64y² = 1600

Process

1.- Divide all the equation by 1600

                            25x²/1600 + 64y²/ 1600 = 1600/1600

-Simplify

                             x²/64 + y²/ 25 = 1

2.- Equation of a horizontal ellipse

                            

3.- Find a, b and c

   a² = 64             a = 8

   b² = 25             b = 5

-Calculate c with the Pythagorean theorem

                  a² = b² + c²

-Solve for c

                  c² = a² - b²

-Substitution

                  c² = 8² - 5²

-Simplification

                 c² = 64 - 25

                 c² = 39

-Result

                 c = √13

4.- Find the center

         C = (0, 0)

5.- Find the vertices

         V1 = (-8, 0)     V2 = (8, 0)

6.- Find the foci

         F1 = (-√13, 0)   F2 = (√13, 0)

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