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Nana76 [90]
3 years ago
14

Finding the sum. imaginary numbers! hellpp

Mathematics
1 answer:
Neko [114]3 years ago
3 0
The "i" in this problem actually doesn't represent imaginary numbers. This is a summation problem which is asking for the sum of (2i+1) for when i = 1 to i = 7.

So (2(1) + 1) + (2(2) + 1) + (2(3) + 1) + (2(4) + 1)... etc...

The summation rules we need to know for this problem are for constants and for a single variable.

When we have a constant, the summation rule is n*c where n is the number of times.

When we have a single variable, the summation rule is n(n+1)/2.

So applying the summation rules where n = 7:

2(7)(7+1)/2 + 1(7)

(7)(8) + 7 = 63

The answer to the summation is 63.
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3y-3.5/3y+6=17/25.5. find the value of y. give the scale factor of the polygon
Mekhanik [1.2K]

Hi the answer to your question is

 

((3y - 3.5) / (3y + 6)) * 25.5 = (17 / 25.5) * 25.5

((3y - 3.5) / (3y + 6)) * 25.5 = 17 (76.5y - 89.25) / (3y + 6) = 17

((76.5y - 89.25) / (3y + 6)) * (3y + 6) = 17 * (3y + 6) 76.5y - 89.25 = 51y + 102 76.5y - 51y = 102 + 89.25

25.5y = 191.25

y = 191.25 / 25.5

<span>y = 7.5</span>

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3 years ago
Rodrigo made 6/8 of a pound of trail mix. If he puts 1/4 of a pound into each bag, how many bags can Rodrigo fill?
ValentinkaMS [17]

Answer:

He can fill 3 bags

Step-by-step explanation:

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What is the area of the sector ?​
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They forget to say "not to scale".  I'm guessing this is trig because I don't see another way to do it.

Let's consider x=chord PQ first.  By the Law of Cosines

x^2 = 3^2 + 5^2 - 2(3)(5) \cos 81^\circ = 34 - 30\cos 81^\circ

We have an isosceles triangle formed by two radii of 9 cm and x=PQ.  By the Law of Cosines again,

x^2 = 9^2 + 9^2 - 2(9)(9) \cos B

x^2 = 162 - 162 \cos B

\cos B = \dfrac{162 - x^2}{162} = 1 - \dfrac{x^2}{162}

\cos B = 1 - \dfrac{34 - 30\cos 81^\circ}{162}

B = \arccos \left(1 - \dfrac{34 - 30\cos 81^\circ }{162} \right)

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A = \dfrac{B}{360^\circ} \pi r ^2

A \approx \dfrac{ \arccos \left(1 - \dfrac{34 - 30\cos 81^\circ}{162} \right) }{360} (3.142)9^2

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