Since segments ST and PQ are parallel, triangles SRT and PRQ are similar due to the AAA postulate. In general, the ratio between the corresponding sides of two similar triangles is constant; therefore,
Furthermore,
Finding PR and RS,
Then,
Solving for PS,
Solve the quadratic equation in terms of PS, as shown below
![\begin{gathered} \Rightarrow PS^2+16PS-132=0 \\ \Rightarrow PS=\frac{-16\pm\sqrt[]{16^2-4(-132)}}{2}=\frac{-16\pm28}{2} \\ \Rightarrow PS=-22,6 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5CRightarrow%20PS%5E2%2B16PS-132%3D0%20%5C%5C%20%5CRightarrow%20PS%3D%5Cfrac%7B-16%5Cpm%5Csqrt%5B%5D%7B16%5E2-4%28-132%29%7D%7D%7B2%7D%3D%5Cfrac%7B-16%5Cpm28%7D%7B2%7D%20%5C%5C%20%5CRightarrow%20PS%3D-22%2C6%20%5Cend%7Bgathered%7D)
And PS is a segment; therefore, it has to be positive.
Hence, the answer is PS=6
Answer:
3, 2, 8, 3, -12
Step-by-step explanation:
d(2x⁴ - 6x²)³/dx
= 3(2x⁴ - 6x²)²(8x³ - 12x)
Answer: 36
Step-by-step explanation:
54/3 = 18 x 2 = 36
Answer:
y = 8 or y = 0
Step-by-step explanation:
Solve for y over the real numbers:
y^2 - 8 y = 0
Factor y from the left hand side:
y (y - 8) = 0
Split into two equations:
y - 8 = 0 or y = 0
Add 8 to both sides:
Answer: y = 8 or y = 0
Answer:
294
Step-by-step explanation:
The distributive property for multiplication is as follows :
a(b+c) = ab + ac
We need to evaluate 6 times 49 i.e. 6(49).
We can write 49 as (50-1)
6(50-1) = 6(50+(-1))
Here, a = 6, b = 50 and c = -1
So,
6(50+(-1)) = 6(50) + 6(-1)
= 300-6
= 294
So, answer is 294. Option (A) is somehow correct.
