The answers to the question are are the equations
y = 0.08x²-1.6x+13
y = 0.08(x-10)²+5
<h3>How to solve for the system of equations</h3>
David starts at (20, 13) and skates along a path that can be modeled by a quadratic function with a vertex at (10, 5).
Vertex form of quadratic function is
y = 
13 = a(x-10)²+5
let x = 20
a(20-10)²+5
13 = 100a + 5
take like terms
13 - 5 = 100a
8 = 100a
divide through by 100
a = 0.08
hence the equation would be
y = 0.08(x-10)²+5
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Answer:
you doing k12 geometry too?
Step-by-step explanation:
Answer:
Options B and D.
Step-by-step explanation:
The general form of sine function

where, |A| is amplitude,
is period,
is phase shift and D is y-intercept.
The general form of cosine function

where, |A| is amplitude,
is period,
is phase shift and D is y-intercept.
In function, 
Amplitude : 
y-intercept : -1
In function, 
Amplitude : 
y-intercept : -1
In function, 
Amplitude : 
y-intercept : 0
In function, 
Amplitude : 
y-intercept : -1
Therefore, the correct options are B and D.
Answer:
<h3>(a) 3^9</h3>
Step-by-step explanation:
<h3> IN EXPONNETIAL FORM :</h3>
<h3>– (a^m× a^n) = (a^m+n)</h3>
<h3>3^4 × 3^5 = 3^4+5 = </h3>
<h2>3^9 </h2>
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