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3 years ago

Which expression is equivalent to 4k+2k?

Mathematics

2 answers:

KiRa [710]3 years ago

6 0

Answer:

Step-by-step explanation:

You can combine both of these terms because they both have the same variable (k). We know that 4+2=6, and the variable stays the same, 6k.

~theLocoCoco

Natalija [7]3 years ago

3 0

Answer:

it equals 6k but an equivalent expression could be 2k + 4k

Step-by-step explanation:

2k + 4k = 4k + 2k

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The answer is A 5^11 I hope that's right

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3 years ago

Each pot of coffee served 10 people. How many tablespoons are needed if you want enough coffee to serve 80 people?

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Step-by-step explanation:

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2 years ago

Find the measure of center: 9, 10, 12, 13, 13, 13, 15, 15, 16, 16, 18, 22, 23, 24, 24, 25

marin [14]

Answer:

Mean : 16.75

Median: 15.5

Mode: 13

Step-by-step explanation:

Given/To Find:

Find the measure of center:

9, 10, 12, 13, 13, 13, 15, 15, 16, 16, 18, 22, 23, 24, 24, 25

Solve:

Mean: Average

Formula: Adding all number in data then divide by the total number in data.

9 + 10 + 12 + 13 + 13 + 13 + 15 + 15 + 16 + 16 + 18 + 22 + 23 + 24 + 24 + 25 = 268

268/16 = 16.75

Median: Middle Number

Formula: Number in the middle

9, 10, 12, 13, 13, 13, 15, 15, 16, 16, 18, 22, 23, 24, 24, 25

15 + 16 = 31

31/2 = 15.5

Mode: Most often number: 13

Kavinsky

7 0

2 years ago

Read 2 more answers

Will mark brainliest! Questions are in the picture!

alexdok [17]

Answer:

52.9 inches .

Step-by-step explanation:

Given that the triangular indentation has an area of 100 in.² and the base and height of this traingle are represented by expressions 3x and x+3 respectively . We need to find out the perimeter to the nearest tenth.

As we know that the area of triangle is ,

$\rm\longrightarrow Area_{\triangle}=\dfrac{1}{2}(base)(height)$

Substituting the respective values,

$\rm\longrightarrow 100\ =\dfrac{1}{2}(x+3)(3x)\\\\\rm\longrightarrow 2(100) = 3x(x+3)\\\\\rm\longrightarrow200 = 3x^2+9x\\\\\rm\longrightarrow 3x^2+9x-200=0$

On using the Quadratic formula , we have;

$\rm\longrightarrow x =\dfrac{-9\pm\sqrt{9^2-4(3)(-200)}}{2(3)} \\\\\rm\longrightarrow x =\dfrac{-9\pm \sqrt{81+1200}}{6}\\\\\rm\longrightarrow x =\dfrac{-9\pm \sqrt{1281}}{6}$