In triangle ABC shown below, side AB is 8 and side AC is 6:

Mathematics

2 answers:

lbvjy [14]2 years ago

8 0

Segment AD is 4, and segment AE is 3. This is because AB is 8, and half of 8 is 4, and then AC is 6, and half of 6 is 3.

Gekata [30.6K]2 years ago

4 0

Answer:

Segment AD is 4, and segment AE is 3.

Step-by-step explanation:

Given,

In triangle ABC,

AB = 8 unit,

AC = 6 unit,

We have to prove :

[tex]DE=\frac{BC}{2}{/tex]

By the Midpoint Theorem, the segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side.

Thus, for proving the required statement we need to prove D and E are midpoints of AB and AC respectively,

That is, AD = DB and AE = EC

∵ AB = 8 ⇒ AD + DB = 8 ⇒ AD + AD = 8 ⇒ 2AD = 8 ⇒ AD = 4

Similarly,

2AE = 6 ⇒ AE = 3

Hence, LAST option is correct.

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I tried using the standard deviation formula but still got the wrong answer. How would I solve this?

nadezda [96]

Answers:

First box = 864

Second box = 3136

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Explanation:

The weird looking E symbol is the greek uppercase letter sigma which stands for "sum". You'll be adding everything in the x^2 column to find that 64+144+256+400 = 864, which is already done for you in the table (as the 864 is at the bottom of the second column, in the "total" row).

In short, you just copy the 864 into the first box.

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For the second box, you'll square the 56 to get 3136

This is because the table shows that adding up all the x values leads to 56

(8+12+16+20 = 56)

So that means $\sum x = 56$ and $\left(\sum x\right)^2 = (56)^2 = 3136$