In a geometric sequence, the ____ between consecutive terms is constant.

I have 47 nickels and dimes worth $4.20. How many of each type of coin do I have?

soldi70 [24.7K]

Answer:

37 dimes and 10 nickels

Step-by-step explanation:

let d = # dimes

let n = # nickels

we can set up a system of equations:

n + d = 47

.05n + .10d = 4.2

if we solve the first equation for 'n' we get:

n = 47-d

now we can substitute this in for 'n' in the second equation:

.05(47-d) + .10d = 4.2

2.35 - .05d + .10d = 4.2

2.35 + .05d = 4.2

subtract 2.35 from each side to get:

.05d = 1.85

d = 1.85÷.05

d = 37

if d+n = 47 and d=37 then n = 10

Check:

.05(10) + .1(37) should equal 4.2

.50 + 3.7 = 4.2 [It Checks Out]

6 0

2 years ago

Someone please help me its urgent<br> What is the equation of the directrix

bija089 [108]

Answer:

Step-by-step explanation:

y=-1

6 0

2 years ago

Read 2 more answers

Mrs. Rivera's class has been keeping track of their recycling for the past four

SOVA2 [1]

They will recycle 24 pounds of paper on week 6

6 0

2 years ago

Prove that tan 10+tan 70'+taniou = tanio tanfo'tam 1oo.

Galina-37 [17]

Question:

Prove that:

$tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)$

Answer:

Proved

Step-by-step explanation:

Given

$tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)$

Required

Prove

$tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)$

Subtract tan(10) from both sides

$- tan(10)+tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100) - tan(10)$

$tan(70) + tan(100) = tan(10). tan(70). tan(100) - tan(10)$

Factorize the right hand size

$tan(70) + tan(100) = -tan(10)(-tan(70). tan(100) + 1)$

Rewrite as:

$tan(70) + tan(100) = -tan(10)(1-tan(70). tan(100))$

Divide both sides by $1-tan(70). tan(100)$

$\frac{tan(70) + tan(100)}{1-tan(70). tan(100)} = \frac{-tan(10)(1-tan(70). tan(100))}{1-tan(70). tan(100))}$

$\frac{tan(70) + tan(100)}{1-tan(70). tan(100)} = -tan(10)$

In trigonometry:

$tan(A + B) = \frac{tan(A) + tan(B)}{1 - tan(A)tan(B)}$

So:

$\frac{tan(70) + tan(100)}{1 - tan(70)tan(100)}$ can be expressed as: $tan(70 + 100)$

$\frac{tan(70) + tan(100)}{1-tan(70). tan(100)} = -tan(10)$ gives

$tan(70 + 100) = -tan(10)$

$tan(170) = -tan(10)$

In trigonometry:

$tan(180 - \theta) = -tan(\theta)$

So:

$tan(180 - 10) = -tan(10)$

Because RHS = LHS

Then:

$tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)$ has been proven

6 0

3 years ago

The equation 3x+4=5x-4 has the solution set {4}. explain why the equation (3x+4)+4=5x-4)+4 also has the solution set {4}

cestrela7 [59]

Notice that the terms in parentheses on both sides of the equation are added to 4.

(3x + 4) + 4 = (5x - 4) + 4

So we can set the equation as.

3x + 4 = 5x - 4

Subtract 3x on both sides of equation.

4 = 2x - 4

Add 4 on both sides of equation.

8 = 2x

Divide both sides of equation by 2.

4 = x

4 is the only value that satisfies the statement.

5 0

3 years ago