4x+7y=2 help . Pls.
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From the problem, the vertex = (0, 0) and the focus = (0, 3)
From the attached graphic, the equation can be expressed as:
(x -h)^2 = 4p (y -k)
where (h, k) are the (x, y) values of the vertex (0, 0)
The "p" value is the difference between the "y" value of the focus and the "y" value of the vertex.
p = 3 -0
p = 3
So, we form the equation
(x -0)^2 = 4 * 3 (y -0)
x^2 = 12y
To put this in proper quadratic equation form, we divide both sides by 12
y = x^2 / 12
Source:
http://www.1728.org/quadr4.htm
From the attached graphic, the equation can be expressed as:
(x -h)^2 = 4p (y -k)
where (h, k) are the (x, y) values of the vertex (0, 0)
The "p" value is the difference between the "y" value of the focus and the "y" value of the vertex.
p = 3 -0
p = 3
So, we form the equation
(x -0)^2 = 4 * 3 (y -0)
x^2 = 12y
To put this in proper quadratic equation form, we divide both sides by 12
y = x^2 / 12
Source:
http://www.1728.org/quadr4.htm
Esta é a trigonometria . Se você desenhar uma linha a partir do topo da casa de luz para o barco, você terá a hypotonuse de um triângulo. Um truque é lembrar que este é um triângulo especial. É um triângulo 30-60-90 , que tem propriedades especiais mostradas na fixação abaixo . por isso sabemos que o lado adjacente que não é o hyposonuse é x√3 . Agora sabemos que x<span>√3 = 20
Solve for x.
x</span><span>√3=20
divide both sides by </span><span>√3.
x=20/(</span><span><span>√3)
</span>Try not to have square roots (</span><span><span>√)</span> in denomenator so multiply top and bottom by </span><span>√3 and get
x=(20</span><span>√3)/3
x is what we are looking for so the answer is </span>
20<span>√3 m </span><span>ou cerca de 34.64 m</span>
Solve for x.
x</span><span>√3=20
divide both sides by </span><span>√3.
x=20/(</span><span><span>√3)
</span>Try not to have square roots (</span><span><span>√)</span> in denomenator so multiply top and bottom by </span><span>√3 and get
x=(20</span><span>√3)/3
x is what we are looking for so the answer is </span>
20<span>√3 m </span><span>ou cerca de 34.64 m</span>