1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nikolay [14]
3 years ago
8

How can i find the slope

Mathematics
1 answer:
Lady_Fox [76]3 years ago
8 0
Rise over run is how you find slope.
You might be interested in
✎Question:Amirah is 4 years elder than Priya and Shirley is 2 years younger than Priya. If the sum of their ages is 47, find the
Gnom [1K]

Answer:

Priya's age = 15

Amirah's age = 19

Shirley's age = 13

Step-by-step explanation:

Let x be the age of Priya.

According to the question,

Amirah's age = x + 4

Shirley's age = x - 2

Their sum is 47.

So,

x + 4 + x + x - 2 = 47

3x + 2 = 47

3x = 47 - 2

3x = 45

x = 45/3

x = 15

So,

Priya's age = 15

Amirah's age = 15 + 4 = 19

Shirley's age = 15 - 2 = 13

7 0
3 years ago
Read 2 more answers
If you buy six pens and one mechanical pencil, you'll get only $1 change from your $10 bill. but if you buy four pens and two me
xxTIMURxx [149]

Let p be the prize of a pen and m the prize of a mechanical pencils. If you buy six pens and one mechanical pencil, you spend 6p+m. We know that this equals 9, because you get 1$ change from a 10$ bill.

Similarly, if you buy four pens and two mechanical pencils, you spend 4p+2m, which is 8$, because now you get a $2 change. Put these equation together in a system:

\begin{cases} 6p+m=9\\4p+2m=8\end{cases}

Now, if you multiply the first equation by 2, the system becomes

\begin{cases} 12p+2m=18\\4p+2m=8\end{cases}

Subtract the second equation from the first:

12p+2m - (4p+2m) = 18-8 \iff 8p = 10 \iff p = \dfrac{10}{8} = 1.25

Plug this value into the first equation to get

6p+m=9 \iff 6\cdot 1.25 +m = 9 \iff 7.5 +m=9 \iff m = 9-7.5 = 1.5

7 0
3 years ago
Firewood can be sold in cords. the wood is cut into equal lengths and stacked evenly in a rack. which geometric shape can be use
Nadya [2.5K]

To estimate the volume of the chord of wood, since the wood exists cut into equal lengths and stacked evenly in a rack then we can use a cylinder as a model.

<h3>What is a cylinder?</h3>

In mathematics, a cylinder exists as a three-dimensional solid that holds two parallel bases joined by a curved surface, at a fixed distance. These bases exist normally circular (like a circle) and the center of the two bases exists joined by a line segment, which exists named the axis.

A cylinder exists as a closed solid that contains two parallel circular bases joined by a curved surface.

To calculate the volume of the chord of wood, since the wood exists cut into equal lengths and stacked evenly in a rack then we can use a cylinder as a model.

To learn more about cylinders refer to:

brainly.com/question/8531193

#SPJ4

7 0
2 years ago
The polynomial x3+8 is equal to
s344n2d4d5 [400]

The polynomial x3+8 is equal to (x+2)(x2-2x+4)


3 0
3 years ago
Read 2 more answers
What is 3 divided by blank equal 36
weqwewe [10]
3÷?=36
multiply both sides by 3 to figure out what "?" is
36*3=108
3÷108=36
?=108
7 0
3 years ago
Other questions:
  • Brielle exercises for 3/4 hour each day for 6 days in a row. Altogether how many hours does she exercise during the 6 days?
    11·2 answers
  • Which expression is the product of (x + 4i)(x − 4i)(x + 4)?
    10·2 answers
  • Identify all of the root(s) of g(x) = (x2 + 3x - 4)(x2 - 4x + 29).
    11·2 answers
  • Proportional ratios are like equivalent fractions, but
    14·1 answer
  • Multiply, if possible.
    6·2 answers
  • Find the volume of the prism
    5·1 answer
  • I need help with number #11
    15·1 answer
  • The sum of 9 and c is less than or<br> equal to 15.
    11·2 answers
  • Maria flips a coin 20 times. The coin only lands on tails 9 times. According to theoretical
    12·1 answer
  • Heellllppppppp pleasee
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!