<span>–6(x – 2y) when x = –3 and y = –5
so
</span><span>–6(x – 2y)
= </span><span>–6(-3 – 2(-5))
= -6(-3 + 10)
= -6(7)
= -42
answer
</span><span>A. -42</span>
Answer and Step-by-step explanation:
C1) (x-1)²+(y+2)²=1 C1 (1,-2) R1 = √1 = 1
C2) (x+5)²+(y-4)²=4 C2 (-5,4) R2 = √4 = 2
DISTANCE FORMULA: d² = (y₂-y₁)²+(x₁-x₂)²
calculating the distances between the 2 center:
d² = (4-(-2))²+(-5-1)² = (6)²+(-6)² = 36 + 36 = 72 ⇒ d = √72
√72 ≈ 8.49
R1 = 1 and R2 = 2
If the circles were secants, d would be < than R1 + R2.
If the circles were tangent, d would be = to R1 + R2
As d > than R1 + R2, we know that the circles do not intercept.
Answer:
-5.126
Step-by-step explanation:
PEMDAS
-4.326 + (-0.32) ÷ 0.4
<u>-0.32 ÷ 0.4</u>
= -0.8
<u>-4.326 + (-0.8)</u>
= -4.326 - 0.8
= -5.126
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